Question

我有一个包含实时数据的流，以及一个流，它基本上划分了属于一起的部分实时数据。现在当有人订阅实时数据流时，我想重播它们的实时数据。但是，我不想记住所有实时数据，只记录自上一次其他流发出值以来的部分。

There is an issue这将解决我的问题，因为有一个重播运算符完全符合我的要求（或者至少我认为）。

目前最简单的方法是什么？有没有比以下更好的方式？

private class ReplayWithLimitObservable<TItem, TDelimiter> : IConnectableObservable<TItem>
{
    private readonly List<TItem> cached = new List<TItem>();
    private readonly IObservable<TDelimiter> delimitersObservable;
    private readonly IObservable<TItem> itemsObservable;
    public ReplayWithLimitObservable(IObservable<TItem> itemsObservable, IObservable<TDelimiter> delimitersObservable)
    {
        this.itemsObservable = itemsObservable;
        this.delimitersObservable = delimitersObservable;
    }

    public IDisposable Subscribe(IObserver<TItem> observer)
    {
        lock (cached)
        {
            cached.ForEach(observer.OnNext);
        }

        return itemsObservable.Subscribe(observer);
    }

    public IDisposable Connect()
    {
        var delimiters = delimitersObservable.Subscribe(
            p =>
                {
                    lock (cached)
                    {
                        cached.Clear();
                    }
                });
        var items = itemsObservable.Subscribe(
            p =>
                {
                    lock (cached)
                    {
                        cached.Add(p);
                    }
                });
        return Disposable.Create(
            () =>
                {
                    items.Dispose();
                    delimiters.Dispose();
                    lock (cached)
                    {
                        cached.Clear();
                    }
            });
}

public static IConnectableObservable<TItem> ReplayWithLimit<TItem, TDelimiter>(IObservable<TItem> items, IObservable<TDelimiter> delimiters)
{
    return new ReplayWithLimitObservable<TItem, TDelimiter>(items, delimiters);
}

Answer 1

这样做你想要的吗？它具有将所有锁定和竞争条件留给Rx专业人员的优势：）

private class ReplayWithLimitObservable<T, TDelimiter> : IConnectableObservable<T>
{
  private IConnectableObservable<IObservable<T>> _source;

  public ReplayWithLimitObservable(IObservable<T> source, IObservable<TDelimiter> delimiter)
  {
    _source = source
      .Window(delimiter) // new replay window on delimiter
      .Select<IObservable<T>,IObservable<T>>(window =>
      {
        var replayWindow = window.Replay();

        // immediately connect and start memorizing values
        replayWindow.Connect();

        return replayWindow;
      })
      .Replay(1); // remember the latest window
  }

  IDisposable Connect()
  {
    return _source.Connect();
  }

  IDisposable Subscribe(IObserver<T> observer)
  {
    return _source
      .Concat()
      .Subscribe(observer);
  }
}

public static IConnectableObservable<TItem> ReplayWithLimit<TItem, TDelimiter>(IObservable<TItem> items, IObservable<TDelimiter> delimiters)
{
    return new ReplayWithLimitObservable<TItem, TDelimiter>(items, delimiters);
}

通过observable限制重放缓冲区

1 个答案: