Question

我正在尝试设置一个mysql数据库以从html表单中捕获信息，但是当我测试它时，它会返回以下错误。该文件与数据库位于同一服务器上。我的php位于错误之下。

警告：mysql_connect（）[function.mysql-connect]：/home/westcl5/public_html/drjseminars.com/thankyou.php上的用户'inmoti6_ted_seminar'@'localhost'（使用密码：YES）拒绝访问92 无法连接：用户'inmoti6_ted_seminar'@'localhost'拒绝访问（使用密码：是）

if( $_POST )
        {
          $con = mysql_connect("localhost","inmoti6_ted_seminar","Polarbear5");

          if (!$con)
          {
            die('Could not connect: ' . mysql_error());
          }

          mysql_select_db("inmoti6_westcl5_ted_sem", $con);

          $users_firstName = $_POST['first_name'];
          $users_lastName = $_POST['last_name'];
          $users_street = $_POST['street'];
          $users_street2 = $_POST['street2'];
          $users_city = $_POST['city'];
          $users_state = $_POST['state'];
          $users_zip = $_POST['zip'];
          $users_country = $_POST['country'];
          $users_email = $_POST['email'];
          $users_telephone = $_POST['telephone'];
          $users_practice = $_POST['practice'];

          $users_firstName = mysql_real_escape_string($users_firstName);
          $users_lastName = mysql_real_escape_string($users_lastName);
          $users_street = mysql_real_escape_string($users_street);
          $users_street2 = mysql_real_escape_string($users_street2);
          $users_city = mysql_real_escape_string($users_city);
          $users_state = mysql_real_escape_string($users_state);
          $users_zip = mysql_real_escape_string($users_zip);
          $users_country = mysql_real_escape_string($users_country);
          $users_email = mysql_real_escape_string($users_email);
          $users_telephone = mysql_real_escape_string($users_telephone);
          $users_practice = mysql_real_escape_string($users_practice);

          $query = "
          INSERT INTO `westcl5_ted_sem`.`ted_seminar` (`First Name`, `Last Name`, `E-mail`, `Phone #`, `Street Address`, `Street Address 2`, `City`, `State`, `Zip Code`, `Country`, `Practice`) VALUES ('$users_firstName', '$users_lastName', '$users_email', '$users_telephone', '$users_street', '$users_street2', '$users_city', '$users_state', '$users_zip', '$users_country', '$users_practice');";

          mysql_query($query);

          mysql_close($con);
        }

Answer 1

问题在于您的密码不匹配。尝试defulat $ CON =的mysql_connect（ “本地主机”， '根'， ''）;代替 $ con = mysql_connect（“localhost”，“inmoti6_ted_seminar”，“Polarbear5”）;

在XAMPP上工作时我也收到了这个错误，但是通过使用我提到的上面那行解决了我的问题。

Answer 2

您需要授予inmoti6_ted_seminar用户权限。以root身份登录到mysql服务器并执行以下SQL，您当然可以设置他们拥有的权限，但我认为您只是想要INSERT。

CREATE USER 'inmoti6_ted_seminar'@'localhost' IDENTIFIED BY 'Polarbear5';
GRANT INSERT ON inmoti6_westcl5_ted_sem.* TO 'inmoti6_ted_seminar'@'localhost';

为什么我收到此错误？

2 个答案: