Question

我试图制作一个猜数游戏＆＃34;在python中，我希望它显示用户必须进行的猜测次数，以便猜测计算机最后生成的随机数。以下是我到目前为止的例子：

    from random import*
a=randrange(1,51)
b=int(input("Can you guess my number?: "))
while a>b:
    b=int(input("Too low, try again: "))
while a<b:
    b=int(input("Too high, try again: "))
while a==b:
    print("You got it! The number was", a)
    break

我希望打印类似于＆＃34的东西;它花了你__猜测＆＃34;在末尾。我将如何跟踪这样的输入数量？我试着四处寻找，但我并不确定如何将它写成文字。

Answer 1

您要做的是摆脱3个while循环，并将其更改为if循环中的while个语句：

from random import*
a=randrange(1,51)
b = 0
guesses = 0 #Initialize a variable to store how many guesses the user has used
while b != a:
    b=int(input("Can you guess my number?: "))
    if a>b:
        b=int(input("Too low, try again: "))
    else:
        b=int(input("Too high, try again: "))
    guesses+=1

print("You got it! The number was", a)
print("You took {} guesses!".format(guesses))

Answer 2

猜测跟踪否。猜测

from random import*

a=randrange(1,51)
guess = 0
while True:
    b=int(input("Can you guess my number?: "))
    guess += 1

    if b==a:
        print("You got it correct")
        break

    elif b>a:
        print("number is higher")

    else:
        print("number is lower")

print("Guesses: ", guess)

Answer 3

d = 74 count = 1

def check(n): if n==d: count += 1 print "You Got the number" elif n>d: print "The number is too high" count += 1 check(int(raw_input('Enter another number'))) elif n<d: print "The no is too low" if count count += 1 check(int(raw_input('Enter something high'))) return count

返回的值是猜测次数

如何跟踪python中while循环的输入数量？

3 个答案: