Question

我和我的朋友通过从互联网上捕捉算法为C编写了代码。我们的程序运行良好，但在某些情况下，我们的长代码有运行时错误。你能帮我把这段代码缩短吗？此代码使用大写和小写字母捕获名称，并将单词的首字母转换为大写，其他字母转换为小写。首先，我们应该给出我们想要的名字数量。

#include <stdio.h>
#include <ctype.h>

int ch, i,n,tool[100];
int main()
{
    int k, j , i;
    char sentence[100][100];
    scanf("%d",&n);
    for(k=0;k<n+1;k++) {
        for (i = 0; (sentence[k][i] = getchar()) != '\n'; i++) {
            ;
        }
        sentence[k][i] = '\0';
        tool[k]=i;
        ch=toupper(sentence[k][0]);
        sentence[k][0]=ch;
        for (j = 1; j < i; j++) {
            if(sentence[k][j-1]==' ')
                ch=toupper(sentence[k][j]);
            else
                ch=tolower(sentence[k][j]);
                sentence[k][j]=ch; 
        }
    }

    for(i=0;i<n+1;i++) {
        for(j=0;j<tool[i];j++) {
            ch=sentence[i][j];
            putchar(ch);
        }

        printf("\n");
    }

    return 0;
}

Answer 1

试试这个..

#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
char *name,*backup_addr, **name_array;
int i,n,j;
main()
{
     char c;
    scanf("%d",&n);
    name_array=malloc(sizeof(char)*1000);
    for(i=0;i<n;i++)
    {
            name_array[i]=malloc(sizeof(char));
            backup_addr=name=malloc(sizeof(char*));
            while(isspace(c=getchar()));
            if(isalpha(c))
            {
                    *name++=toupper(c);
                    for(j=0;(isalpha(c=getchar()))!='\n'&&c!='\n';j++,name++)
                                            *name=tolower(c);
            }
            *name='\0';
            name=backup_addr;
            name_array[i]=name;
    }
    for(i=0;i<n;i++)
            printf("%s\n",name_array[i]);
}

Answer 2

这是一个明显更短的。并且在方便的功能形式中：

#include <stdio.h>

/** convert string to sentence case.
*  returns string with initial cap and single i converted to uppercase.
*/
char *str2sentence (char *str)
{
    if (!str) return NULL;

    char *p = str;
    if ('a' <= *p && *p <= 'z')    /* convert first to upper */
        *p -= 32;
    p++;

    for ( ; *p; p++)    /* convert remaining to lower, except a single 'i' to upper 'I' */
    {
        if (*(p - 1) == 0x20 && *(p + 1) == 0x20)
        {
            if (*p == 'i')
                *p -= 32;
            else
                if ('A' <= *p && *p <= 'Z' && *p != 'I')
                    *p += 32;
        }
        else
            if ('A' <= *p && *p <= 'Z')
                *p += 32;
    }

    return str;
}

int main (void) {

    char *str = NULL;

    printf ("\n Enter a string to convert to sentence case ([enter] to quit)\n");

    while (printf ("\n  input : ") && scanf ("%m[^\n]%*c", &str) == 1)
        printf ("  result: %s\n", str2sentence (str));

    return 0;
}

<强>输出：

./bin/str2sentence

 Enter a string to convert to sentence case ([enter] to quit)

  input : this IS A StrinG tO ConvERt.
  result: This is a string to convert.

  input : oR maYBe aNOTher OnE.
  result: Or maybe another one.

  input :

Answer 3

你可以试试这个。

#include<stdio.h> 
#include<stdlib.h>
#include<string.h>
main()
{
    char *array[100],*p;
    int i=0,j,n,k;
    scanf("%d",&n);
    for (n=n+1 ; n > 0 ; n--) { p=(char *)malloc(100);
            array[i++]=p;   
            for (k=0; (*p=getchar()) != '\n' && *p !=EOF ;p++, k++); *p='\0';       

            for ( p=p-k; *p !='\0'; p++) {  
                    if (isspace(*p) )
                            continue;
                    *p=toupper(*p); p++;
                    for( ; *p!=' ' && *p!='\0' ;p++ )
                            *p=tolower(*p);
                    if ( *p=='\0' ) p--;
            }
    }               

    for (j=0;  j<i ; j++)
            printf("%s\n",array[j]);
 }

输入就像你的程序一样。

在C中有运行时错误

3 个答案: