Question

很抱歉，如果这是一个noob问题，我仍然是php的初学者....

我需要从函数返回的数组中回显Country键。我尝试过尝试从数组中获取值的各种方法，但每次都没有得到我想要的结果。

我想将返回数组中的'country'值设置为变量，以便对值执行if参数。请帮忙......

我试图在下面做的样本 -

<?php

$country = get_shipping_address()['country']

if ( $country=="GB" ) {

do this;

}

?>

以下是功能 -

function get_shipping_address() {

    if ( ! $this->shipping_address ) {

         if ( $this->shipping_address_1 ) {

             // Formatted Addresses
             $address = array(
                 'address_1'     => $this->shipping_address_1,
                 'address_2'     => $this->shipping_address_2,
                 'city'          => $this->shipping_city,
                 'state'         => $this->shipping_state,
                 'postcode'      => $this->shipping_postcode,
                 'country'       => $this->shipping_country
              );

              $joined_address = array();

             foreach ( $address as $part ) {

                  if ( ! empty( $part ) ) {
                      $joined_address[] = $part;
                  }
             }

            $this->shipping_address = implode( ', ', $joined_address );
        }
     }

     return $this->shipping_address;
 }

Answer 1

您的问题是您在自己的功能中执行此操作：

foreach ( $address as $part ) {
    if ( ! empty( $part ) ) {
        $joined_address[] = $part;
    }
}
$this->shipping_address = implode( ', ', $joined_address );

这样做会使string包含数组的所有值。例如：

derp, derp, derp, derp, derp, derp

您想要的是返回$address variable。

return $address;

让你的功能看起来像这样：

function get_shipping_address() {
    $address = array();

    if (!$this->shipping_address) {

        if ($this->shipping_address_1) {

            // Formatted Addresses
            $address = array(
                'address_1' => $this->shipping_address_1,
                'address_2' => $this->shipping_address_2,
                'city' => $this->shipping_city,
                'state' => $this->shipping_state,
                'postcode' => $this->shipping_postcode,
                'country' => $this->shipping_country
            );

        }
    }

    return $address;
}

Answer 2

感谢Darren，（以及其他评论过的人）这就是诀窍。

我创建了一个新函数并将其更改为仅返回我需要的值，因为我只需要知道国家/地区值。所以改变了下面的功能。谢谢你的帮助!!

function get_my_shipping_address() {

    if ( ! $this->shipping_address ) {

        if ( $this->shipping_address_1 ) {

            // Formatted Addresses
            $address = array(
                'address_1'     => $this->shipping_address_1,
                'address_2'     => $this->shipping_address_2,
                'city'          => $this->shipping_city,
                'state'         => $this->shipping_state,
                'postcode'      => $this->shipping_postcode,
                'country'       => $this->shipping_country
            );
        }
    }

    return $address['country'];
}

从PHP中的函数返回的数组中的Echo键值

2 个答案: