Question

我有一个看起来像这样的数组，它由：

生成

$file = fopen($savedSource,"r");

            while(! feof($file)) {
                $data = (fgetcsv($file));
            }

Array
(
    [0] => First Name
    [1] => Last Name
    [2] => Title
    [3] => Company / Account
    [4] => Email
    [5] => Lead ID
    [6] => Profile Image
Zelayas
    [7] => Zelayas
    [8] => 
    [9] => Kramer
    [10] => zel@somewhere.com
    [11] => 123456
    [12] => https://media.com/0f48c22.jpg
Kanngiesser
    [13] => Kanngiesser
    [14] => 
    [15] => Johnson
    [16] => kanngie@somewhere.com
    [17] => 7891234
    [18] => https://media.com/135f3b7.jpg

我希望能够将这些URL存储到一个简单的（无嵌套）数组中，以便结果变为：

Array
    (
        [0] => https://media.com/0f48c22.jpg
        [1] => https://media.com/135f3b7.jpg

===编辑=== 从选定的答案中，我基本上能够实现我的目标。

        $new_array = array();
        foreach($data as $a){
            if(substr( $a, 0, 4 ) === "http"){
                array_push($new_array, $a);
            }
        }

结果，$ new_array正在给我

Array
(
    [0] => https://media.com/0f48c22.jpg
Kanngiesser
    [1] => https://media.com/135f3b7.jpg
Mostovoy

所以看起来脚本正在查看当前行的最后一个字段以及下一行AS ONE FIELD的第一个字段。

Answer 1

您可以使用substr检测字符串开头的http。

$new_array = array();
foreach($old_array as $a){
    if(substr( $a, 0, 4 ) === "http"){
        array_push($new_array, $a);
    }
}

Answer 2

$new=array();
foreach ($array as $check){

if(substr($check,0,4)=='http')
$new[]=$check;
}

搜索嵌套数组，仅返回一列中的url值

2 个答案: