Question

我一直在修改骰子游戏猪的代码。我将它修改为滚动2个骰子而不是一个骰子。当你滚动一个时，它会转到下一个玩家转弯，你的任何一个点都不会与你之前的得分保持一致。好吧当你滚动两个我需要它将分数重置为0并打印出我的消息＆＃34; Snake Eyes !!你的分数设置为0＆＃34;。问题是两条信息都打印出来用于蛇眼，当你滚动一条信息时，两条信息都被滚动。分数也不会重置。

编辑*我已使用冲突的打印消息修复了代码，但仍然无法在分割蛇形时将分数重置为0

from random import randint

playercount = 2
maxscore = 100
safescore = [0] * playercount
player = 0
score=0

while max(safescore) < maxscore:
    if player == 0:
        rolling = 0
        if score < 17 and score + safescore[player] < maxscore:
            rolling = 1
    else:
        rolling = input("Player %i: (%i, %i) Rolling? (Y) "
            % (player, safescore[player], score)).strip().lower() in {'yes', 'y', ''}
    if rolling:
        rolled = randint(1, 6)
        rolled2 = randint(1, 6)
        print('  Rolled %i' % rolled)
        print('  Rolled %i' % rolled2)
        if rolled ==1 and rolled2 ==1:
                print('  Snake Eyes!! your score is set to 0')
                score=0

        elif rolled == 1:
            print('  Bust! you lose %i but still keep your previous %i'
                  % (score, safescore[player]))
            score, player = 0, (player + 1) % playercount
        elif rolled2 == 1:
            print('  Bust! you lose %i but still keep your previous %i'
                  % (score, safescore[player]))
            score, player = 0, (player + 1) % playercount


        else:
            score += rolled + rolled2
    else:
        safescore[player] += score
        if safescore[player] >= maxscore:
            break
        print('  Sticking with %i' % safescore[player])
        score, player = 0, (player + 1) % playercount

print('\nPlayer %i wins with a score of %i' %(player, safescore[player]))

Answer 1

您需要更正支票的顺序。现在你的＆＃34;滚动了一个＆＃34;检查发生在＆＃34;滚动两个＆＃34;检查，因此当两个滚动时它将执行。如果你把＆＃34;两个＆＃34;首先检查并使用else-if结构使两者独占，您将获得所需的行为：

if rolled==1 and rolled2==1:
    # snake eyes
elif rolled==1:
    # a single one
else:
    # all other cases

另外，请注意，您目前只检查两个骰子是否出现一个，或者第一个骰子是否出现一个。你可能还想检查第二个骰子是否出现了。

我在这个游戏中有一个相互矛盾的代码

1 个答案: