这是我用C编写的代码:
#include<stdio.h>
struct Node
{
int info;
struct Node *next;
};
void init_Node(struct Node *n)
{
n->next = NULL;
}
struct Node *front = NULL;
void display()
{
struct Node *rear = front;
if(rear == NULL)
printf("List is empty!\n");
else
{
printf("[%i]-->",rear->info);
rear = rear->next;
}
printf("NULL");
printf("\n");
}
void addEnd(int x)
{
struct Node *n = malloc(sizeof(struct Node));
struct Node *rear = front;
n->info = x;
if(front == NULL)
front = n;
else
{
while(rear->next != NULL)
rear = rear->next;
rear->next = n;
rear = n;
}
display();
}
void deleteEnd()
{
struct Node *rear = front;
if(front == NULL)
printf("Stack is Empty!");
else
{
while(rear->next->next != NULL)
{
rear = rear->next;
}
printf("Popped : %i\n", rear->next->info);
rear->next = NULL;
display();
}
}
int main()
{
struct Node *n = malloc(sizeof(struct Node));
init_Node(n);
clrscr();
addEnd(23);
addEnd(45);
addEnd(8);
addEnd(57);
deleteEnd();
addEnd(98);
deleteEnd();
getch();
return 0;
}
以下输出是使用类在C ++中完成实现时的输出。 程序的输出应该是这个 -
但我的代码输出是这样的 -
修改 添加while()循环并添加n-&gt; next = NULL;输出结果如下:
我哪里错了?
答案 0 :(得分:3)
您需要进行两项更改:
void display()
{
struct Node *rear = front;
if(rear == NULL)
printf("List is empty!\n");
else
{
// CHANGE 1: You need a while loop here
while(rear != NULL) {
printf("[%i]-->",rear->info);
rear = rear->next;
}
}
printf("NULL");
printf("\n");
}
void addEnd(int x)
{
struct Node *n = malloc(sizeof(struct Node));
struct Node *rear = front;
n->info = x;
// CHANGE 2: You need to clear n->next to NULL.
n->next = NULL;
if(front == NULL)
front = n;
else
{
while(rear->next != NULL)
rear = rear->next;
rear->next = n;
rear = n;
}
display();
}
答案 1 :(得分:0)
在你的函数中,addEnd()需要将下一个指针初始化为零。所以,就在行n-> info = x之后;添加一行n-> next = 0;