这就是我在做的事情:
WITH cte AS (
SELECT * FROM TimeDim
)
SELECT t.TimeDimPK, c.ID
FROM CTE AS t
LEFT OUTER JOIN TABLE c ON c.TimeDimFK = t.TimeDimPK
ORDER BY t.TimeDimPK
WHERE c.ID = 1
结果,缺少日期,如下所示:
TimeDimPK ID
20120930 1
20121231 1
20130131 1
我想要的是什么
TimeDimPK ID
20120930 1
20121031 NULL
20121130 NULL
20121231 1
20130131 1
答案 0 :(得分:2)
看起来您的WHERE
子句正在摆脱其他日期。试试这个:
WITH cte
AS ( SELECT TimedimPK
FROM TimeDim
)
SELECT t.TimeDimPK ,
c.ID
FROM cte t
LEFT OUTER JOIN TABLEname c ON c.TimeDimFK = t.TimeDimPK
WHERE c.ID = 1
OR c.ID IS NULL
ORDER BY t.TimeDimPK
答案 1 :(得分:0)
您可以尝试使用"数字/日期生成器",此查询将填写所有缺失的日期,然后选择该月的最后一天。我不确定您的所有数据详情,所以我现在给您两个建议:
1 - 紧凑的建议:
DECLARE @minDate DATETIME, @maxDate DATETIME;
SELECT @minDate = MIN(TimeDimPK), @maxDate = MAX(TimeDimPK) FROM TimeDim;
WITH DateGenerator AS
(
--Create a list with a lot of dates from @minDate
SELECT TimeDimPK = CONVERT(DATE, DATEADD(dd, ROW_NUMBER() OVER (ORDER BY OBJECT_ID), @minDate)) FROM sys.objects
)
--List all days, including missing days
SELECT TimeDimPK
, c.ID
FROM DateGenerator n
LEFT JOIN AnotherTable c ON c.TimeDimFK = n.TimeDimPK
WHERE
--Stop the number generator at the last day of the last month from the cte table
n.TimeDimPK <= CONVERT(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0, @maxDate )+1,0)))
--This will get the last day of every month
AND TimeDimPK = CONVERT(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,TimeDimPK)+1,0)))
2 - 建议使用cte子句,如果你想用它做一些调整:
WITH NumberGenerator AS
(
--Create a number list 1,2,3,4,5,6,7,8,++
SELECT Number = ROW_NUMBER() OVER (ORDER BY OBJECT_ID) FROM sys.objects
), cte AS (
--Your cte query with a date number based on the days between the firts and current days
SELECT
TimeDimPK = CONVERT(DATETIME, TimeDimPK)
--Get the number of days to add from the first day in your table
, DateNumber = DATEDIFF(dd, MIN(TimeDimPK) OVER (), TimeDimPK)
FROM #TimeDim
), TableWithMissingDates AS
(
--Fill missing days
SELECT TimeDimPK = CONVERT(DATE, DATEADD(dd, n.Number - 1, MIN(t.TimeDimPK) OVER ()))
, c.ID
FROM NumberGenerator n
LEFT JOIN cte t ON t.DateNumber = n.Number
LEFT JOIN #Test2 c ON c.TimeDimFK = t.TimeDimPK
--Stop the number generator at the last day of the last month from the cte table
WHERE CONVERT(DATE, DATEADD(dd, n.Number - 1, (SELECT MIN(TimeDimPK) FROM cte))) < CONVERT(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0, (SELECT MAX(TimeDimPK) FROM cte) )+1,0)))
)
SELECT * FROM TableWithMissingDates
WHERE
--This will get the last day of every month
TimeDimPK = CONVERT(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,TimeDimPK)+1,0)))
两个查询都会返回相同的表格: