我在CodeIgniter中做应用程序,我不知道如何在CodeIgniter中比较电子邮件和db,请任何人帮助我。
控制器
public function signup()
{
$this->load->view('signup');
}
public function savedata(){
$this->load->library('form_validation');
$this->form_validation->set_rules('firstname', 'firstname', 'required');
$this->form_validation->set_rules('lastname', 'lastname', 'required');
if ($this->form_validation->run() == TRUE) // Only add new option if it is unique
{
$result = $this->account_model->insert();
if($result > 0)
{
$data['message'] = "Added successfully";
$this->load->view('signup',$data);
}
else
{
$this->index();
}
}
else
{
$this->load->view('signup');
}
}
如何发送电子邮件以及是否存在电子邮件。
答案 0 :(得分:8)
假设您有user
表和email
列。因此,您必须在表单验证中添加此行
$this->form_validation->set_rules('email','Email','required|valid_email|is_unique[users.email]');
注意强>
并且需要在email
列中添加唯一索引
答案 1 :(得分:5)
添加规则:
$this->form_validation->set_rules('email', 'Email', 'callback_rolekey_exists');
在同一个控制器中:
function rolekey_exists($key) {
$this->roles_model->mail_exists($key);
}
在模型中,
function mail_exists($key)
{
$this->db->where('email',$key);
$query = $this->db->get('users');
if ($query->num_rows() > 0){
return true;
}
else{
return false;
}
}
答案 2 :(得分:0)
//in controller
public function usernameExist($username)
{
$user = $this->Model-> usernameExist($username);
if ($user) {
$this->form_validation->set_message(
'usernameExist',
'Username is already exist.'
);
return false;
} else {
return true;
}
}
答案 3 :(得分:0)
function username_Exist($key)
{
$this->db->where('username', $key);
$query = $this->db->get('signup');
if ($query->num_rows() > 0) {
return true;
} else {
return false;
}
}
//在模型中输入
答案 4 :(得分:0)
$this->form_validation->set_rules('username', 'User', 'trim|required|callback_username_Exist');
//type in controller in form validation
答案 5 :(得分:0)
最佳方式
$this->form_validation->set_rules(
'email', 'Email', 'valid_email|required|is_unique[usr_user.user_email]',
array('is_unique' => 'This %s already exists.')
);