Question

关于我何时选择添加客户端的任何想法，当我输入客户端ID时，程序会为该条目崩溃？

#include <stdio.h>
#include <stdlib.h>

struct client
{
    int clID;
    char cname;
    char caddress;
    char cemail;
    int cfees;
    int ceID;
    char cename;
}typedef client;

struct employee
{
    int empID;
    char ename;
    double erate;
    double ehours;
    double esalary;
    int ecID;
}typedef employee;

void mainMenu();
void clientMenu();
void empMenu();
void getClient(client* pcli);
void getEmp(employee* pemp);
void payroll(employee* pemp);
void dispPay(employee* pemp);
void dispClient(client* pcli);
void dispEmployee(employee* pemp);

int main()
{
    client cli[100];
    client* pcli = &cli[0];
    employee emp[20];
    employee* pemp = &emp[0];
    int answer = -1;
    int mchoice;
    int cchoice;
    int echoice;
    int ccount;
    int ecount;
    int input[9];
    int* psearchclientID;
    int i;

printf("Do you wish to start the program? 1 for yes 2 for no: ");
scanf("%d", &answer);
if(answer ==1)
{
    while(mchoice != 3)
    {
        mainMenu();
        scanf("%d", &mchoice);
        switch(mchoice)
        {
        case 1: while(cchoice != 3)
        {
            clientMenu();
            scanf("%d", &cchoice);
            switch(cchoice)
            {
            case 1: getClient(pcli + i);
                    ccount++;
                break;
            case 2: printf("Enter the client ID to search for: ");
                    psearchclientID = fgets(input, 9, stdin);
                    strtok(input, "\n");
                    for(i = 0; i < 1; i++)
                    {
                        if(strcmpi(psearchclientID, (pcli->clID + i)) == 0)
                            printf("Client found at position %d\n", i);
                        else
                            printf("Client not found!");
                    }//end for
                break;
            }//end client switch
        }//end client while
        cchoice = 0;
            break;
        case 2: while(echoice != 4)
        {
            empMenu();
            scanf("%d", &echoice);
            switch(echoice)
            {
            case 1: getEmp(pemp + i);
                    ecount++;
                break;
            case 2: payroll(pemp + i);
                    dispPay(pemp + i);
                break;
            case 3:
                break;
            }//end emp switch
        }//end emp while
        echoice =0;
            break;
        }//end switch
    }//end main while
}//end if
else if(answer ==2)
{
    printf("Goodbye!");
    exit(0);
}
return 0;
}//end main

void mainMenu()
{
    printf("1-Client Menu\n"
           "2-Employee Menu\n"
           "3-Quit\n");
    printf("Enter a choice from the menu: ");
}//end mainMenu

void clientMenu()
{
    printf("1-Add a client\n"
           "2-Search client\n"
           "3-Go Back to Main Menu\n");
    printf("Enter a choice from the menu: ");
}//end clientMenu

void empMenu()
{
    printf("1-Add an Employee\n"
           "2-Process an Employee(payroll)\n"
           "3-Search Employee\n"
           "4-Go Back to Main Menu\n");
    printf("Enter a choice from the menu: ");
}//end empMenu

这是输入客户信息的代码

void getClient(client* pcli)
{
    printf("Enter client ID: ");
    scanf("%d", &pcli->clID);
    printf("Enter client name: ");
    scanf("%s", &pcli->cname);
    printf("Enter client address: ");
    scanf("%s", &pcli->caddress);
    printf("Enter client email: ");
    scanf("%s", &pcli->cemail);
    printf("Enter monthly service fees:" );
    scanf("%d", &pcli->cfees);
}//end getClient

void getEmp(employee* pemp)
{
    printf("Enter employee ID: ");
    scanf("%d", &pemp->empID);
    printf("Enter employee name: ");
    scanf("%s", &pemp->ename);
    printf("Enter employee hourly rate: ");
    scanf("%lf", &pemp->erate);
    printf("Enter employee hours worked: ");
    scanf("%lf", &pemp->ehours);
}//end getEmp

void payroll(employee* pemp)
{
    pemp->esalary = pemp->erate * pemp->ehours;
}//end payroll

void dispPay(employee* pemp)
{
    printf("Employee ID %d\nEmployee Salary: %2.2f\n", pemp->empID, pemp->esalary);
}//end dispPay

这是显示信息的地方

  void dispClient(client* pcli)
    {
        printf("Client ID: %d\n Name: %s\n Address: %s\n Email: %s\n Monthly fees: %d\n Employee assigned: %d\n Employee name: %s\n", pcli->clID, pcli->cname, pcli->caddress, pcli->cemail, pcli->cfees, pcli->ceID, pcli->cename);
    }//end dispClient

    void dispEmployee(employee* pemp)
    {
        printf("Employee ID: %d\n Name: %s\n Hourly Rate: %2.2f\n Hours worked: %2.2f\n Salary: %2.2f\n Client(s) assigned: %s\n", pemp->empID, pemp->ename, pemp->erate, pemp->ehours, pemp->esalary, pemp->ecID);
    }//end dispEmp

Answer 1

在阅读时，您不会在&（字符串）中包含%s（地址）运算符。例如，在函数getClient中，使用 printf("Enter employee name: "); scanf("%s", pemp->ename);

这是您计划中的问题之一。

Answer 2

您的clientMenu switch语句添加客户端调用：

case 1: getClient(pcli + i);

有可能在i未初始化的例程中，因此它可能是任何，并且很可能超出了100元素数组的范围。在这种情况下，getClient很可能会在它不拥有的内存中运行，从而使您的程序容易崩溃。

这可能还有不止一个问题在起作用。正如其他人所说，有关崩溃的更多信息会有所帮助。

它为什么一直崩溃？

2 个答案: