Question

我想使用product在quantity中插入每个产品的多个mysql和foreach loop，但下面的代码只插入我在input field中输入的最后一个产品。我使用jquery添加更多字段，以便我可以输入更多product和每个产品的数量。

这是我用来在我的表单中添加更多输入字段的jquery demo

<?php
  if(isset($_POST['submit'])){
     //process the form   

     $qtys = array($_POST["product_description"] => $quantity = $_POST["quantity"]);
     foreach($qtys as $item => $qty){

     $date = $_POST["date"];
     $customer_name = $_POST["customer_name"];
     $status = $_POST["status"];

     $query  = "INSERT INTO orders (";
     $query .= "date, customer_name, product_description, quantity, status";
     $query .= ") VALUES (";
     $query .= "'{$date}', '{$customer_name}', '{$item}', {$qty}, {$status}";
     $query .= ")"; 
     $order_set = mysqli_query($connection, $query);
     if($order_set){
       redirect_to("index.php");
     }

     }



  } else {
    // failed

  }


?>

我的表格

<form action="order.php" method="post">
  <div class="newOrder">
    <p><span>Date</span><input type="date" value="2014-12-01" name="date" /></p>
    <p><span>Name</span>
    <select name="customer_name">


     <?php
      while($customer = mysqli_fetch_assoc($customers_set)){  ?>

        <option><?php echo $customer['customer_name']; ?></option>

      <?php } ?>
      <?php mysqli_free_result($customers_set); ?>

    </select>

    </p>  


    <div id="input_fields">

    <p><span>Product Description</span>
    <select name="product_description[]">
     <?php
      while($product = mysqli_fetch_assoc($product_set)){  ?>

        <option><?php echo $product['product_description']; ?></option>

      <?php } ?>
      <?php mysqli_free_result($product_set); ?>
    </select>
    <input value="0" type="text" name="quantity []" />
    </p>

    </div>
    <a href="#" class="more">Add More Product</a>


    <p class="radio">
      <input type="radio" name="status" value="0" checked />For delivery&nbsp;&nbsp;
      <input type="radio" name="status" value="1" />For payment confirmation&nbsp;&nbsp;
      <input type="radio" name="status" value="2" />Reserved items&nbsp;&nbsp;
    </p>


    <input type="submit" name="submit" value="Create Order" />   
  </div>
</form>

Answer 1

那是因为你在第一个循环结束时重定向 - 将重定向移出循环 - 它应该循环并插入每一个 - 也是最明显但我忽略了你循环通过一个数组只有1个元素 - 因为你在顶部$ qtys设置它 - 在$ _POST上做一个var转储，让我看看发布了什么。

<?php

  error_reporting(E_ALL);
  if(isset($_POST['submit'])){


     $errors = array(); 

         $date = $_POST["date"];
         $customer_name = $_POST["customer_name"];
         $status = $_POST["status"];

     foreach($_POST['product'] as $key => $desc){
         // do this to other ones too
         $qty = filter_var($_POST['quantity'][$key], FILTER_SANITIZE_NUMBER_INT);
         $desc = filter_var($desc, FILTER_SANITIZE_STRING); 

         $query  = "INSERT INTO orders (";
         $query .= "date, customer_name, product_description, quantity, status";
         $query .= ") VALUES (";
         $query .= "'{$date}', '{$customer_name}', '{$desc}', {$qty}, {$status}";
         $query .= ")"; 
         $order_set = mysqli_query($connection, $query);
         if(!$order_set){
            $errors = $query; 
         }
     }// end of for each 

    if(empty($errors)){
        // no errors redirect to home page 

        header("Location: index.php");
    }

    // if it makes it here then there are errors. 
    echo ' Errors in the sql ---- ' ; 
    var_dump($errors); 
    echo 'POST VALUES';
    var_dump($_POST); 
  } 

?>












<form action="order.php" method="post">
  <div class="newOrder">
    <p><span>Date</span><input type="date" value="2014-12-01" name="date" /></p>
    <p><span>Name</span>
    <select name="customer_name">


     <?php
      while($customer = mysqli_fetch_assoc($customers_set)){  ?>

        <option value="<?php echo $customer['customer_name']; ?>"><?php echo $customer['customer_name']; ?></option>

      <?php } ?>
      <?php mysqli_free_result($customers_set); ?>

    </select>

    </p>  


    <div id="input_fields">

    <p><span>Product Description</span>
    <select name="product[]">
     <?php
      while($product = mysqli_fetch_assoc($product_set)){  ?>

        <option value="<?php echo $product['product_description']; ?>"><?php echo $product['product_description']; ?></option>

      <?php } ?>
      <?php mysqli_free_result($product_set); ?>
    </select>
    <input value="0" type="text" name="quantity[]" />
    </p>

    </div>
    <a href="#" class="more">Add More Product</a>


    <p class="radio">
      <input type="radio" name="status" value="0" checked />For delivery&nbsp;&nbsp;
      <input type="radio" name="status" value="1" />For payment confirmation&nbsp;&nbsp;
      <input type="radio" name="status" value="2" />Reserved items&nbsp;&nbsp;
    </p>


    <input type="submit" name="submit" value="Create Order" />   
  </div>
</form>

Answer 2

我认为你需要使用输入名称作为数组

错误是您的数据过度使用print_r($_POST)以检查是否已发布所有值

使用

<input type="text" name="product []" />
<input type="text" name="quantity []" />

<input type="text" name="product []" />
<input type="text" name="quantity []" />

<input type="text" name="product []" />
<input type="text" name="quantity []" />

你的if会让你到index

 foreach($qtys as $item => $qty){

     $date = $_POST["date"];
     $customer_name = $_POST["customer_name"];
     $status = $_POST["status"];

     $query  = "INSERT INTO orders (";
     $query .= "date, customer_name, product_description, quantity, status";
     $query .= ") VALUES (";
     $query .= "'{$date}', '{$customer_name}', '{$item}', {$qty}, {$status}";
     $query .= ")"; 
     $order_set = mysqli_query($connection, $query);
     // if($order_set){   
       // redirect_to("index.php");
     // }

     can use  "if(!$order_set)" instead

 }

Answer 3

尝试 -

 $query  = "INSERT INTO orders (";
 $query .= "date, customer_name, product_description, quantity, status";
 $query .= ") VALUES ";
 $values = array();
 $date = $_POST["date"];
 $customer_name = $_POST["customer_name"];
 $status = $_POST["status"];
 foreach($qtys as $item => $qty){
     $values[] = "('{$date}', '{$customer_name}', '{$item}', {$qty}, {$status})";
 }
 $query .= implode(',', $values);

Answer 4

根据此代码，我认为必须发布持久连接

请在每次插入后关闭连接尝试此操作。并且还考虑 redirect_to（）也是错误的。

如何使用foreach循环在mysqli中插入多个`product`和`quantity`

4 个答案: