Question

我正在尝试使用我的create_list在1-6之间生成10,000个数字。 count_list假设计算生成的1,2,3,4,5,6的数量，主函数假设附加两个，然后打印每个的结果。顺便说一下，我刚开始使用def，所以对我很轻松;）

def count_list(my_list, c):
     amount_one=0
     amount_two=0
     amount_three=0
     amount_four=0
     amount_five=0
     amount_six=0
     or number in my_list:
         if number==1:
             amount_one+=1
         elif number==2:
             amount_two+=1
         elif number==3:
             amount_three+=1
         elif number==4:
             amount_four+=1
         elif number==5:
             amount_five+=1
         elif number==6:
             amount_six+=1
     return amount_one
     return amount_two
     return amount_three
     return amount_four
     return amount_five
     return amount_six
def create_list(n):
     import random
     my_list=[]
     for i in range(10000):
         n=random.randint(1,6)
         my_list.append(n)
     return my_list
def main():
     hello=count_list(create_list)
     print "1-",count_list()[0]
     print "2-",count_list()[1]
     print "3-",count_list()[2]
     print "4-",count_list()[3]
     print "5-",count_list()[4]
     print "6-",count_list()[5]

 main()

Answer 1

您可以使用参数n来确定列表中要生成的数字数

def create_list(n):
    import random
    my_list = []
    for i in range(n):
        my_list.append(random.randint(1,6))
    return my_list

要计算列表中的项目，一个直接的方法就是这样

def count_list(l):
    c = {1:0, 2:0, 3:0, 4:0, 5:0, 6:0}  # initialize dictionary
    for key in c:
        c[key] = l.count(key)
    return c

现在我们可以在main

中调用上述函数

def main():
    nums = create_list(1000)
    counts = count_list(nums)
    for i in range(1,7):
        print(i, counts[i])

测试

为了好玩，这里有一些稍微更先进的方法，以更有效的方式做同样的事情

def create_list(n):
    import random
    return [random.randint(1,6) for _ in range(n)]  # using a list comprehension

def count_list(l):
    from collections import Counter  # using the Counter class
    return Counter(l)

def main():
    nums = create_list(1000)
    counts = count_list(nums)
    for i in range(1,7):
        print(i, counts[i])

Answer 2

使用collections.Counter进行计数，只需将create_list返回的数字列表传递给它：

from collections import Counter
import random


def create_list():
    my_list = []
    for i in range(10000):
        n = random.randint(1, 6)
        my_list.append(n)
    return my_list


print(Counter(create_list()))

Counter({1: 1702, 4: 1695, 6: 1692, 3: 1688, 5: 1651, 2: 1572})

如果您想要3个最常见的数字等，请使用.most_common(3)：

print(Counter(create_list()).most_common(3))

Answer 3

您可以使用字典将计数与相应的数字进行映射：

def count_list(my_list):
    from collections import defaultdict
    dict = defaultdict(int)

    for x in my_list:
        dict[x] += 1

    return dict


def create_list(a,b):
     import random
     my_list=[]
     for i in range(10000):
         n=random.randint(a,b)
         my_list.append(n)
     return my_list

def main():
     lst = create_list(1,6)
     dict = count_list(lst)
     print(dict)


if __name__=="__main__":
    main()

我需要让我的主要功能正常工作

3 个答案: