我的JSON:
{
"name": "asdf",
"age": "15",
"address": {
"street": "asdf"
}
}
如果street为null,使用JsonSerialize.Inclusion.NON_NULL
,我可以获得..
{
"name": "asdf",
"age": "15",
"address": {}
}
但是我希望得到这样的东西..(当地址不为空时,它是一个新的/空对象。但是街道是空的。)
{
"name": "asdf",
"age": "15"
}
我认为有自定义序列化功能,如JsonSerialize.Inclusion.VALID_OBJECT
。
在Address类中添加isValid()方法然后如果返回true则序列化,否则不要序列化。
但我不知道如何进一步/哪个类要覆盖。这是可能的还是其他任何观点?请建议。
添加了课程
public static void main(String[] args) {
ObjectMapper mapper = new ObjectMapper();
Customer customer = new Customer();
customer.setName("name");
customer.setAddress(new Address());
mapper.writeValue(new File("d:\\customer.json"), customer);
}
@JsonSerialize(include = JsonSerialize.Inclusion.NON_NULL)
public class Customer {
private String name;
private Address address;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Address getAddress() {
return address;
}
public void setAddress(Address address) {
this.address = address;
}
}
@JsonSerialize(include = JsonSerialize.Inclusion.NON_NULL)
public class Address {
private String street;
public String getStreet() {
return street;
}
public void setStreet(String street) {
this.street = street;
}
}
注意:我现在不担心反序列化。即丢失地址对象。
提前致谢。
答案 0 :(得分:1)
使用序列化的自定义JSON对象非常简单。
我在我的项目中写了一个claas我给你一个如何在项目中实现它的线索
贷款申请(POJO类)
import java.io.Serializable;
import java.util.List;
import org.webservice.business.serializer.LoanApplicationSerializer;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
@JsonSerialize(using=LoanApplicationSerializer.class)
public class LoanApplication implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
private double amount;
private User borrowerId;
private String businessType;
private String currency;
private int duration;
private Date lastChangeDate;
private long loanApplicationId;
private String myStory;
private String productCategory;
private String purpose;
private Date startDate;
private String status;
private String type;
private String salesRepresentative;
现在包含使用序列化逻辑的自定义的LoanApplicationSerializer
类................
package org.ovamba.business.serializer;
import java.io.IOException;
import org.webservice.business.dto.LoanApplication;
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.SerializerProvider;
public class LoanApplicationSerializer extends JsonSerializer<LoanApplication> {
@Override
public void serialize(LoanApplication prm_objObjectToSerialize, JsonGenerator prm_objJsonGenerator, SerializerProvider prm_objSerializerProvider) throws IOException, JsonProcessingException {
if (null == prm_objObjectToSerialize) {
} else {
try {
prm_objJsonGenerator.writeStartObject();
prm_objJsonGenerator.writeNumberField("applicationId", prm_objObjectToSerialize.getLoanApplicationId());
prm_objJsonGenerator.writeStringField("status", prm_objObjectToSerialize.getStatus());
prm_objJsonGenerator.writeNumberField("amount", prm_objObjectToSerialize.getAmount());
prm_objJsonGenerator.writeNumberField("startdate", prm_objObjectToSerialize.getStartDate().getTime());
prm_objJsonGenerator.writeNumberField("duration", prm_objObjectToSerialize.getDuration());
prm_objJsonGenerator.writeStringField("businesstype", prm_objObjectToSerialize.getBusinessType());
prm_objJsonGenerator.writeStringField("currency", prm_objObjectToSerialize.getCurrency());
prm_objJsonGenerator.writeStringField("productcategory", prm_objObjectToSerialize.getProductCategory());
prm_objJsonGenerator.writeStringField("purpose", prm_objObjectToSerialize.getPurpose());
prm_objJsonGenerator.writeStringField("mystory", prm_objObjectToSerialize.getMyStory());
prm_objJsonGenerator.writeStringField("salesRepresentative", prm_objObjectToSerialize.getSalesRepresentative());
} catch (Exception v_exException) {
//ExceptionController.getInstance().error("Error while Serializing the Loan Application Object", v_exException);
} finally {
prm_objJsonGenerator.writeEndObject();
}
}
}
}
Hope This may help u alot. Thanks..
答案 1 :(得分:0)
您可以使用@JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
示例:
@JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
public myClass{
// attributes and accessors
}
找到一些有用的信息