这是我所面临的困境......
我有2张桌子
create table #orders
(orderNumber int,qty int,sku varchar(250),barcode varchar(250))
create table #allItemsInBox
([id] int,[date] date,[localsku] varchar(250),[box] varchar(250),barcode varchar(250))
我需要加入[barcode]
上的2个表格,#allItemsInBox
请注意[#allItemsInBox].[id]
是唯一的,[#allItemsInBox]
中的其他字段可能不是
我将如何做这样的事情?
sample data:
[#orders]
(1,0,'10','10')
(1,0,'20','20')
(3,0,'20','20')
(4,0,'30','30')
(5,0,'40','40')
(6,0,'50','50')
#allItemsInBox
(1,'12/3/2014',10,'Box1',10)
(2,'12/2/2014',20,'Box2',20)
(3,'12/1/2014',20,'Box3',20)
(4,'11/30/2014',20,'Box4',20)
(5,'11/29/2014',30,'Box5',30)
(6,'11/28/2014',40,'Box6',40)
(7,'11/27/2014',60,'Box8',60)
(8,'11/27/2014',50,'Box10',50)
#output
(ordernumber int,uniqueitemID int,localsku varchar(250),box varchar(250))
(1,1,10,'Box1')
(1,2,20,'Box2')
(3,3,10,'Box3')
(4,5,30,'Box5')
(5,6,40,'Box6')
(6,8,50,'Box10')
答案 0 :(得分:1)
这很快但有效。根据数据的大小,这可能不是性能方面的最佳方式。但这会给你一个开始
DECLARE @orders TABLE (
orderNumber int,
qty int,
sku varchar(250),
barcode varchar(250)
)
DECLARE @allItemsInBox TABLE (
[id] int,
[date] date,
[localsku] varchar(250),
[box] varchar(250),
barcode varchar(250)
)
INSERT INTO @orders VALUES
(1,0,'10','10'),
(1,0,'20','20'),
(3,0,'20','20'),
(4,0,'30','30'),
(5,0,'40','40'),
(6,0,'50','50')
INSERT INTO @allItemsInBox VALUES
(1,'2014-12-03',10,'Box1',10),
(2,'2014-12-02',20,'Box2',20),
(3,'2014-12-01',20,'Box3',20),
(4,'2014-11-30',20,'Box4',20),
(5,'2014-11-29',30,'Box5',30),
(6,'2014-11-28',40,'Box6',40),
(7,'2014-11-27',60,'Box8',60),
(8,'2014-11-27',50,'Box10',50)
SELECT
orders.orderNumber AS ordernumber
,(SELECT TOP 1 allItems.id FROM @allItemsInBox allItems WHERE allItems.barcode = orders.barcode AND allItems.id >= orders.orderNumber ORDER BY allItems.id) AS uniqueitemID
,(SELECT TOP 1 allItems.localsku FROM @allItemsInBox allItems WHERE allItems.barcode = orders.barcode AND allItems.id >= orders.orderNumber ORDER BY allItems.id) AS localsku
,(SELECT TOP 1 allItems.box FROM @allItemsInBox allItems WHERE allItems.barcode = orders.barcode AND allItems.id >= orders.orderNumber ORDER BY allItems.id) AS box
FROM
@orders orders
结果:
ordernumber uniqueitemID localsku box
1 1 10 Box1
1 2 20 Box2
3 3 20 Box3
4 5 30 Box5
5 6 40 Box6
6 8 50 Box10
编辑:我更新了答案。您现在拥有与示例/问题
中指定的输出相同的输出