Question

ref_number 是xxtable中的一列，它具有多次相同的值。对于每5个值，我需要将别名类型增加1 - 最大类型 100

**Select type,ref_number
 from (select '70' type
        , ref_number
        from xxtable)**

查询结果应如下所示

type       ref_number
----       ----------
70         1001
70         1001
70         1001
70         1001
70         1001
71         1001
71         1001
71         1001
71         1001
71         1001
72         1001
72         1001
72         1001
 .
 .
 .
100

Answer 1

如果我理解正确，你想要这个：

select least(trunc(70+count(*)/5), 100), ref_number
from xxtable
group by ref_number

编辑：所以，我认为应该有效

select least(trunc(70+(row_number() over (partition by ref_number order by ref_number)-1)/5), 100), ref_number
from xxtable

编辑：这应该有效：

select type, LISTAGG(ref_number, '') WITHIN GROUP (ORDER BY ref_number) 
from(
select least(trunc(70+(row_number() over (partition by ref_number order by ref_number)-1)/5), 100) type, ref_number
from xxtable)
group by type, ref_number

注意：我无法尝试，所以我可能会在那里添加另一个错误。

Answer 2

如果不同type ref_number正在增加，您仍然无法指定。如果没有，user2179887的想法就足够了。如果是，则必须添加另一个逻辑。如果没有多个（＆＃34;嵌套＆＃34;）分析函数的使用，我担心它是不可能的：

with xxtable as (
  select column_value as ref_number
  from table(sys.KU$_OBJNUMSET(
    1001,1001,1001,1001,1001,1001,1001,1001,1001,1001,1001,1001,1001,1001,
    1002,1002,1002,
    1003,1003,1003,1003,1003,1003,
    1004,
    1005,1005,1005,1005,1005,1005,
    1006
  ))
)
select
  70 + trunc(((row_number() over (partition by x.ref_number order by null)) - 1)/5) as user2179887_corrected_type,
  x.ref_number,
  70 + trunc(((row_number() over (partition by x.ref_number order by null)) - 1)/5) + nvl(g.gs,0) as increasing_type
from xxtable x
join (
  select
    ref_number,
    sum(trunc((count(*) + 4) / 5))
      over (order by ref_number rows between unbounded preceding and 1 preceding) as gs
  from xxtable
  group by ref_number
) g on g.ref_number = x.ref_number

说明：

with - 子句仅用于Oracle内置集合中的数据模拟，您可以安全地复制其余的查询
对于每个唯一ref_number，g子选择预先计算所有行的贡献ref_number到结果type
analytical sum over收集以前值的这些总和（窗口条款中为1 preceding）
条件＆＃39;输入max 100＆＃39;为简洁而省略

我认为这超出了分析功能的可理解范围。也许使用model子句可以提供更可读的结果。无论如何，感谢有趣的问题，让我更多地了解分析功能： - ）。

pl / sql查询一次获取n条记录

2 个答案: