Question

我正在尝试使用基本表单将数据添加到我的应用程序中，但我已经设置了一个结构，将所有内容分成“项目”。

所有内容都会被您选择的项目过滤掉，并且项目会为用户提供更多密钥。

然后我的网址设置为：

** //后端/项目

** //后端/项目[PROJID] /能力

然后，当我添加'capability'元素时，我需要从URL或kwargs中读取'project'id

如何访问capability_project（在呈现表单模板时）

即。提交按钮将用户重定向回正确的项目页面

<form id="capability-form" method="post" action="backend/projects/{{ project_capability }} /capabilities">

我认为因为它有很多对它返回迭代器错误。我该怎么做？如何在添加项目时确保project_id值始终正确？ //编辑以更新NoReverseMatch错误即时无法访问表单中的kwargs。

NoReverseMatch at /backend/projects/1/capabilities/add/
Reverse for 'capability-list' with arguments '()' and keyword arguments '{}' not found. 0 pattern(s) tried: []
Request Method: POST
Request URL:    http://c9589d:8000/backend/projects/1/capabilities/add/

并进一步跟踪信息

Request information

GET No GET data
POST Variable   Value
status  u'12'
domain  u'2'
capability_num  u'1'
level   u'a'
description u'asasd'
submit  u'Create Capability'
project u'1'
csrfmiddlewaretoken u'RW2vMwu3BhCOOhDTRaSeCglDSBCctqeF'
name    u'asdsd'

models.py

class Project(models.Model):
    proj_name = models.CharField()
    assigned_to = models.ManyToManyField(User, related_name='assigned_to')

class Capability(models.Model):
    name = models.CharField()
    project = models.ManyToManyField(Project)
    current_status = models.BooleanField()
    future_status = models.NullBooleanField()

class Function(models.Model):
    name = models.CharField()
    capability = models.ForeignKey(Capability)
    current_status = models.BooleanField()
    future_status = models.NullBooleanField()

views.py

class Add_Capability(CreateView):
    template_name = 'backend/add_capability.html'
    model = Capability
    fields = ['name', 'description', 'status', 'capability_num', 'project', 'domain']
    form_class = CapabilityForm

forms.py

class CapabilityForm(forms.ModelForm):
    name = forms.CharField(max_length=255, help_text="Please enter a name for the capability")
    description = forms.CharField(max_length=255, help_text="Please enter a description for the capability")
    status = models.CharField(max_length=255, choices=STATUS_CHOICES, default="Approved")
    capability_num = forms.DecimalField(max_digits=5, decimal_places=4, help_text="Enter a number")
    project = models.ManyToManyField(Project, null=True)
    level = models.CharField(max_length=1, choices=LEVELS_CHOICES, default="Approved")
    domain = models.ManyToManyField(Domain)

    class Meta:
        model = Capability
        fields = ('name', 'description',)

urls.py

# /backend/1/capabilities
url(r'^projects/(?P<capability_project>\d+)/capabilities/$', views.CapabilityList.as_view(), name='capability-list'),

# /backend/capabilities/add - Add capabilities
url(r'^projects/(?P<capability_project>\d+)/capabilities/add/$', views.Add_Capability.as_view(), name='add-capability'),

# /backend/projects
url(r'^projects/$', views.ProjectList.as_view(), name='projects'),

Answer 1

在views.py中，您可以通过以下方式访问kwargs：

class Add_Capability(CreateView):
    template_name = 'backend/add_capability.html'
    model = Capability
    fields = ['name', 'description', 'status', 'capability_num', 'project', 'domain']
    form_class = CapabilityForm
    project_id = False

    def get_success_url(self):
        self.success_url = reverse('project-detail')+self.kwargs['capability_project']+'/'
        return super(Add_Capability, self).get_success_url()

从url（或kwargs）获取基于django类的表单的id

1 个答案: