Question

我尝试获取用户输入以填充具有＆lt; = 1且＆lt; = 24的数字的变量。目前它只发送到else语句并打印这两行并等待另一个输入。即使输入满足三个条件。

EG。我进入1.这应该满足所有三个条件？

程序应该为用户提供与输入问题相对应的错误。

如果未输入整数，则仅要求输入数字。如果该数字是<1或> 24，则应该要求仅在这两个点之间输入数字。

    while (length1 == Integer.MIN_VALUE) {
        System.out.print("Enter the Length of wall 1: ");
        if (scan.hasNextInt() && 1<=length1 && length1<=24) {
            length1 = scan.nextInt();
        }
        else if (length1<1 && 24<length1) {
            System.out.println("Error Error");
            System.out.println("Please only enter numbers between 1 and 24.");
            scan.next();
        } else {
            System.out.println("Error Error");
            System.out.println("Please only enter numbers.");
            scan.next();
        }
    }

Answer 1

除了一个错误的&&之外，首先应该读取nextInt。

while (true) {
    System.out.print("Enter the Length of wall 1: ");
    if (scan.hasNextInt()) {
        length1 = scan.nextInt();
        if (1 <= length1 && length1 <= 24) {
            break:
        }
        System.out.println("Error Error");
        System.out.println("Please only enter numbers between 1 and 24.");
    } else {
        System.out.println("Error Error");
        System.out.println("Please only enter numbers.");
        scan.next();
    }
}

Answer 2

使用以下代码：

while (length1 == Integer.MIN_VALUE) {
    System.out.print("Enter the Length of wall 1: ");
    if (scan.hasNextInt() && 1<=length1 && length1<=24) {
        length1 = scan.nextInt();
    }
    else if (length1<1 || 24<length1) {
        System.out.println("Error Error");
        System.out.println("Please only enter numbers between 1 and 24.");
        scan.next();
    } else {
        System.out.println("Error Error");
        System.out.println("Please only enter numbers.");
        scan.next();
    }
}

if方法有多个条件时出错

2 个答案: