我是初学者编码器,我的项目要求我对文本文件进行分类。 我正在打开的txt文件是这样的: (这不完全是txt文件看起来就像是当我复制并经过它时,它看起来太乱了。还有另一个专栏因为某些原因只填充了'map'这个词)
MAG UTC DATE-TIME LAT LON DEPTH Region 4.3 2014/03/12 20:16:59 25.423 -109.730 10.0 GULF OF CALIFORNIA 5.2 2014/03/12 20:09:55 36.747 144.050 24.2 JAPAN 5.0 2014/03/12 20:08:25 35.775 141.893 24.5 JAPAN 4.8 2014/03/12 19:59:01 38.101 142.840 17.6 Japan 4.6 2014/03/12 19:55:28 37.400 142.384 24.7 JAPAN 5.0 2014/03/12 19:45:19 -6.187 154.385 62.0 GUINEA
我希望输出是这样的:
[[japan,'4.3','5.2','5.0','4.8','4.6'],[加利福尼亚湾,4.3],[几内亚,5.0]]
我目前的编码: (第一个for循环中的vlist [7:]给出了区域名称,第二个for循环中的j [1]给出了magtitude数字。)
def myOpen(filepointer):
header = filepointer.readline()
regions = []#gathers up all the names of the regions without repeating them
maglist = []#matchs with naems and numbers
filelines = []#list of lines in txt file
for aline in filepointer:#reades each line
vlist = aline.split()#turns lines into lists
filelines.append(vlist)
if not vlist[7:] in regions:#makes list of names without repeat
regions.append(vlist[7:])
regions.sort()
for j in filelines:#gets each file line
for names in regions:#each name
if names == j[7:]:
num = j[1]
names.append(float(num))
mags.append(names)
return maglist
def main():
myFile = open('earthquakes.txt','r')
quakes = myOpen(myFile)
myFile.close()
print(quakes)
main()
给出了这个输出:
<[> [[japan,'4.3'],[加利福尼亚湾,4.3],[几内亚,5.0]]
我想知道为什么它只获得了其他地区出现的第一个数字,而不是其他地区。
答案 0 :(得分:0)
您可以:使用itertools.groupby
,lambda
,map
,str.split
,str.lower
和str.join
如果您的文件如下所示:
MAG UTC DATE-TIME LAT LON DEPTH Region
4.3 2014/03/12 20:16:59 25.423 -109.730 10.0 GULF OF CALIFORNIA
5.2 2014/03/12 20:09:55 36.747 144.050 24.2 JAPAN
5.0 2014/03/12 20:08:25 35.775 141.893 24.5 JAPAN
4.8 2014/03/12 19:59:01 38.101 142.840 17.6 Japan
4.6 2014/03/12 19:55:28 37.400 142.384 24.7 JAPAN
5.0 2014/03/12 19:45:19 -6.187 154.385 62.0 GUINEA
这是工作代码:
>>> import itertools
>>> f = open('file.txt')
>>> [[" ".join(x),list(map(lambda z:z[0],list(y)))] for x,y in itertools.groupby(sorted(list(map(str.split,map(str.lower,list(f)[1:]))),key=lambda x:" ".join(x[6:])),key=lambda x:x[6:])]
[['guinea', ['5.0']], ['gulf of california', ['4.3']], ['japan', ['5.2', '5.0', '4.8', '4.6']]]
让我解释一下:
>>> f = open('file.txt')
>>> k = list(map(str.lower,list(f)[1:])) # convert all lines to lower case and leave 1st line
>>> k
['4.3 2014/03/12 20:16:59 25.423 -109.730 10.0 gulf of california\n', '5.2 2014/03/12 20:09:55 36.747 144.050 24.2 japan\n', '5.0 2014/03/12 20:08:25 35.775 141.893 24.5 japan\n', '4.8 2014/03/12 19:59:01 38.101 142.840 17.6 japan\n', '4.6 2014/03/12 19:55:28 37.400 142.384 24.7 japan\n', '5.0 2014/03/12 19:45:19 -6.187 154.385 62.0 guinea\n']
>>> k = list(map(str.split,k)) # it will split the lines on whitespaces
>>> k
[['4.3', '2014/03/12', '20:16:59', '25.423', '-109.730', '10.0', 'gulf', 'of', 'california'], ['5.2', '2014/03/12', '20:09:55', '36.747', '144.050', '24.2', 'japan'], ['5.0', '2014/03/12', '20:08:25', '35.775', '141.893', '24.5', 'japan'], ['4.8', '2014/03/12', '19:59:01', '38.101', '142.840', '17.6', 'japan'], ['4.6', '2014/03/12', '19:55:28', '37.400', '142.384', '24.7', 'japan'], ['5.0', '2014/03/12', '19:45:19', '-6.187', '154.385', '62.0', 'guinea']]
>>> k = sorted(k,key = lambda x:" ".join(x[6:])) # it will sort the k on Region
>>> k
[['5.0', '2014/03/12', '19:45:19', '-6.187', '154.385', '62.0', 'guinea'], ['4.3', '2014/03/12', '20:16:59', '25.423', '-109.730', '10.0', 'gulf', 'of', 'california'], ['5.2', '2014/03/12', '20:09:55', '36.747', '144.050', '24.2', 'japan'], ['5.0', '2014/03/12', '20:08:25', '35.775', '141.893', '24.5', 'japan'], ['4.8', '2014/03/12', '19:59:01', '38.101', '142.840', '17.6', 'japan'], ['4.6', '2014/03/12', '19:55:28', '37.400', '142.384', '24.7', 'japan']]
>>> [[" ".join(x),list(map(lambda z:z[0],list(y)))] for x,y in itertools.groupby(k,key = lambda x:x[6:])]
[['guinea', ['5.0']], ['gulf of california', ['4.3']], ['japan', ['5.2', '5.0', '4.8', '4.6']]]