Question

SELECT  
    tbl_team.te_name, 
    tbl_player.pl_name, 
    tbl_scorer.sc_time
FROM            
    tbl_scorer
    INNER JOIN tbl_team on tbl_scorer.sID_team = tbl_team.pID_team
    INNER JOIN tbl_player on tbl_scorer.sID_player = tbl_player.pID_player
    INNER JOIN tbl_games on tbl_scorer.sID_game = tbl_games.pID_game
WHERE tbl_games.pID_game = 9

这给了我这样的东西

    +-------+----------+---+
    | TeamA | PlayerAA | 4 |
    +-------+----------+---+
    | TeamB | PlayerBA | 4 |
    +-------+----------+---+
    | TeamB | PlayerBB | 2 |
    +-------+----------+---+
    | TeamA | PlayerAA | 1 |
    +-------+----------+---+
    | TeamB | PlayerBB | 1 |
    +-------+----------+---+

我想要的是通过团队列的appaerances来计算这个结果，如此

+-------+----------+---+
| TeamB | PlayerBA | 4 |
+-------+----------+---+
| TeamB | PlayerBB | 2 |
+-------+----------+---+
| TeamB | PlayerBB | 1 |
+-------+----------+---+
| TeamA | PlayerAA | 4 |
+-------+----------+---+
| TeamA | PlayerAA | 1 | 
+-------+----------+---+

我可以使用

查询按团队名称分组的行数

SELECT  
        tbl_team.te_name, 
        count(tbl_team.te_name)
    FROM            
        tbl_scorer
        INNER JOIN tbl_team on tbl_scorer.sID_team = tbl_team.pID_team
        INNER JOIN tbl_player on tbl_scorer.sID_player = tbl_player.pID_player
        INNER JOIN tbl_games on tbl_scorer.sID_game = tbl_games.pID_game
    WHERE tbl_games.pID_game = 9 group by tbl_team.te_name

但如何将它们组合起来以获得正确的顺序？

Answer 1

对于特定的给定数据\

 select dh.* from 
(SELECT  
tbl_team.te_name, 
tbl_player.pl_name, 
tbl_scorer.sc_time
FROM            
tbl_scorer
INNER JOIN tbl_team on tbl_scorer.sID_team = tbl_team.pID_team
INNER JOIN tbl_player on tbl_scorer.sID_player = tbl_player.pID_player
INNER JOIN tbl_games on tbl_scorer.sID_game = tbl_games.pID_game
WHERE tbl_games.pID_game = 9) dh,    
(
SELECT  
tbl_team.te_name, 
count(tbl_team.te_name) rep
FROM            
tbl_scorer
INNER JOIN tbl_team on tbl_scorer.sID_team = tbl_team.pID_team
INNER JOIN tbl_player on tbl_scorer.sID_player = tbl_player.pID_player
INNER JOIN tbl_games on tbl_scorer.sID_game = tbl_games.pID_game
WHERE tbl_games.pID_game = 9
) xad
where dh.te_name=xad.te_name
order by xad.rep desc,dh.sc_time desc;

Answer 2

你可以用这个：

;WITH CTE AS (
SELECT  
    tbl_team.te_name, 
    tbl_player.pl_name, 
    tbl_scorer.sc_time
FROM            
    tbl_scorer
    INNER JOIN tbl_team on tbl_scorer.sID_team = tbl_team.pID_team
    INNER JOIN tbl_player on tbl_scorer.sID_player = tbl_player.pID_player
    INNER JOIN tbl_games on tbl_scorer.sID_game = tbl_games.pID_game
WHERE tbl_games.pID_game = 9)


SELECT a.*
FROM CTE a
CROSS APPLY (SELECT COUNT(te_name) as Count_te FROM CTE b WHERE a.te_name = b.te_name) x
ORDER BY x.Count_te DESC, a.te_name, a.sc_time DESC

按一列中的出现次数排序并查询其他列

2 个答案: