如何解析字典列表

时间：2014-12-03 05:27:31

标签： python list dictionary

我从Web服务获得以下字典列表：

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"B"}, {"user_id": null, "name": "image.size", "resource_id": "cbaa1562-c6c0-4922-b5ec-95ae71d0ebda", "source": "openstack", "meter_id": "Y2JhYTE1NjItYzZjMC00OTIyLWI1ZWMtOTVhZTcxZDBlYmRhK2ltYWdlLnNpemU=\n", "project_id": "f8bd7d5659a74eb6a6c47650a43511b5", "type": "gauge", "unit": "B"}]

我想： 1）将此列表解析为单独的词典 2）从每个字典中提取值

因此，伪代码将是：

for listItem in my_list:
    userId = listItem["user_id"]
    name = listItem["name"]
    resourceId = listItem["resource_id"]

实现此目的的python语法是什么？

2 个答案:

答案 0 :(得分：1)

也许这个简单的例子是说明性的：

from pprint import pprint
import json

json_string = '[{"name": "Jean Luc", "rank": "Captain"}, {"name": "Worf", "rank": "Commander"}]'

officers = json.loads(json_string)
for officer in officers:
    pprint(officer)

您希望查看Python的json库[1]，将JSON从字符串/文件解析为正常的数据结构，如列表和dicts。

[1] https://docs.python.org/2/library/json.html

答案 1 :(得分：0)

listItem[0]["user_id"]
listItem[0]["name"]
listItem[0]["resource_id"]

类似于下一个数组

listItem[1]["user_id"]
listItem[1]["name"]
listItem[1]["resource_id"]

并使用

检查数组的长度 
len(listItem)
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