将2个不同的mySql结果合并到一个表中

Question

我喜欢将两个不同的mysql结果合并到一个表中

第一个sql是

select     sum(cnt)             
from  xx_dept_hardware_cnt_v            

，结果将是

sum(cnt)
---------
67

第二个sql是

select sum(cnt)             
from xx_dept_emp_cnt_v          
where org_cb_id in (select cb_id from xx_dept_hardware_cnt_v)   

结果将是

sum(cnt)
---------
62

如何编写能给我结果的sql？

sum(cnt)        sum(cnt)
---------       ---------
67              62

Answer 1

您可以将两个子查询放在select中。我更喜欢将它们放在from子句中并使用cross join：

select cnt1, cnt2
from (select sum(cnt) as cnt1           
      from xx_dept_hardware_cnt_v  
     ) h cross join
     (select sum(cnt) as cnt1           
      from xx_dept_emp_cnt_v          
      where org_cb_id in (select cb_id from xx_dept_hardware_cnt_v) 
     ) d     

Answer 2

select sum(cnt), (select sum(s.cnt) from xx_dept_hardware_cnt_v s where s.org_cb_id in (select x.cb_id from xx_dept_hardware_cnt_v x) ) from xx_dept_hardware_cnt_v

您可以在select中使用子查询。