Question

我有这个程序可以在我定义的长度和宽度的板上绘制简单的参数方程。它编译得很好，但在图形的不同位置打印函数的多个实例。如果有人可以帮我弄清楚为什么我得到这个输出，我会非常感激。我在整个代码中包含了注释，以帮助理解正在发生的事情。我没有足够的声誉来发布输出的图片，但如果你编译并执行它，你会看到我在说什么。

#include <iostream>
#include <cstdlib>
#include <unistd.h>
#include <time.h>
#include <cmath>
using namespace std;

#define N 25
#define M 60

/*
  This function prints the board each time it is called and places an *
  in the place corresponding to the value of the function.
*/
void print_board(char p[M][N]) {
    int i, j;
    for (i=0; i<=N; i++) {
        for (j=0; j<=M; j++)
                 if (i==0)      cout << '=';
            else if (j==0)      cout << '|';
            else if (i==N)      cout << '=';
            else if (j==M)      cout << '|';
            else if (p[i][j]== '*') cout << '*';
            else            cout << ' ';
        cout << endl;
    }
}
/*
  These functions accepts an integer for time and computes a value for x and y
  for the parametirc equations given and returns each.
*/
int fx(int t) {

    int x = t;

    return x;
}

int fy(int t) {

    //int y = 5 * sin(0.2 * t) + 15;
    int y = (pow(t,2)/60) - t + 25;

    return y;
}

/*
  This function copies the old board and comoputes what the new board is.
*/
void next_board(char p[M][N], int t) {
    int i, j;

    //copies the old board
    int q[M][N];
    for (i=0; i<=N; i++) {
        for (j=0; j<=M; j++) {
            q[i][j] = p[i][j];
        }
    }

    //creates the new board
    int x, y;
    for (i=0; i<=N; i++) {
        for (j=0; j<=M; j++) {
            x = fx(t);
            y = fy(t);

            if (i == y && j == x) {
                p[i][j] = '*';  //stores an * for the values of x and y
            }
        }
    }

}

int main() {

    char p[M][N];

    print_board(p);

    int t = 0;
    while(t <= M) {
        cout << string(80, '\n');

        next_board(p , t);
        print_board(p);
        usleep(20000);

        t++;
    }

    return 0;
}

请帮助并感谢所有尝试的人！

Answer 1

您计划中的所有地方

char p[M][N]

将其更改为

char p[N][M]

你应该得到你期望的结果，你的程序中的混合轴

如果您愿意，可以使用整个工作代码

#include <iostream>
#include <cstdlib>
#include <unistd.h>
#include <time.h>
#include <cmath>
#include <string>
using namespace std;

#define N 25
#define M 60

/*
This function prints the board each time it is called and places an *
in the place corresponding to the value of the function.
*/
void print_board(char p[N][M]) {
    int i, j;
    for (i = 0; i <= N; i++) {
        for (j = 0; j <= M; j++)
            if (i == 0)      cout << '=';
            else if (j == 0)      cout << '|';
            else if (i == N)      cout << '=';
            else if (j == M)      cout << '|';
            else if (p[i][j] == '*') cout << '*';
            else            cout << ' ';
            cout << endl;
    }
}
/*
These functions accepts an integer for time and computes a value for x and y
for the parametirc equations given and returns each.
*/
int fx(int t) {

    int x = t;

    return x;
}

int fy(int t) {

    //int y = 5 * sin(0.2 * t) + 15;
    int y = (pow(t, 2) / 60) - t + 25;

    return y;
}

/*
This function copies the old board and comoputes what the new board is.
*/
void next_board(char p[N][M], int t) {
    int i, j;

    //copies the old board
    int q[M][N];
    for (i = 0; i <= N; i++) {
        for (j = 0; j <= M; j++) {
            q[i][j] = p[i][j];
        }
    }

    //creates the new board
    int x, y;

    for (i = 0; i <= N; i++) {

        for (j = 0; j <= M; j++) {
            x = fx(t);
            y = fy(t);

            if (i == y && j == x) {
                p[i][j] = '*';  //stores an * for the values of x and y
            }
        }
    }

}

int main() {

    char p[N][M];

    print_board(p);

    int t = 0;
    while (t <= M) {
        cout << string(80, '\n');

        next_board(p, t);
        print_board(p);
        usleep(20000);

        t++;
    }

    return 0;
}

为什么我的grapher会打印多个函数实例？ C ++

1 个答案: