创建一个查询，显示已进行超过2次维修的任何车辆。显示Vehicle SerialNo，Year，Make，Model和RepairOrders的计数
我有两张表来提取信息：
RepairOrder表
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| OrdNo | Odometer | DateIN | TimeRecvd | TimeFinish | PhoneWnRdy | SerialNo |
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| 1 | 50000 | 10/3/2011 | 1:31 PM | 5:30 PM | Yes | AZXS230I87 |
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| 2 | 30000 | 12/2/2011 | 4:20 PM | 5:00 PM | Yes | IOMEQ54397 |
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| 3 | 6000 | 12/4/2011 | 9:00 AM | 1:30 PM | Yes | JKLP7IIIJF |
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| 4 | 75000 | 12/5/2011 | 11:15 AM | 6:00 PM | No | AZXS230I87 |
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| 5 | 15000 | 12/7/2011 | 11:53 AM | 3:30 PM | No | TYYYI87590 |
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| 6 | 55000 | 12/7/2011 | 4:42 PM | 5:30 PM | No | BHGY08631Q |
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| 7 | 25500 | 12/8/2011 | 11:53 AM | 4:00 PM | Yes | V121BHD481 |
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| 8 | 125000 | 12/9/2011 | 2:30 PM | 3:30 PM | Yes | PLJFVC5609 |
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| 9 | 60800 | 12/12/2011 | 12:03 PM | 5:00 PM | Yes | XCVY760PIQ |
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| 10 | 11000 | 12/13/2011 | 11:41 AM | 1:15 PM | Yes | THYDF55639 |
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| 11 | 55060 | 12/15/2011 | 12:04 PM | 4:45 PM | No | MNMJ7H6098 |
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| 12 | 25600 | 12/17/2011 | 9:08 AM | 12:30 PM | Yes | THYDF55639 |
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| 13 | 56000 | 12/17/2011 | 3:14 PM | 4:00 PM | No | QWER9LK982 |
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车辆表
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| SerialNo | Year | Make | Model | LicenseNo | LicenseState | Cylinders | CustNo |
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| AZXS230I87 | 2009 | Ford | Skylark | 145UKI | WA | 4 | 10 |
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| BHGY08631Q | 2006 | Chevrolet | Blazer | 567WER | WA | 8 | 7 |
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| GHL39789UI | 2012 | Honda | Del Sol | 123XYZ | MT | 4 | 13 |
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| IOMEQ54397 | 2008 | Buick | Regal | 367ASZ | WA | 8 | 2 |
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| JHMCCF673Q | 2000 | Honda | Civic Si | 367ABC | WA | 4 | 8 |
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| JHMEC3348H | 1993 | Buick | Corolla | 345XYZ | WA | 6 | 5 |
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我编写了这段代码，我正在努力解决如何从两个不同的表中提取信息的问题。
SELECT Vehicle.SerialNo, Vehicle.Year, Vehicle.Make, Vehicle.Model
FROM Vehicle
Where (Vehicle.SerialNo) IN(Select (RepairOrder.SerialNo)
from RepairOrder
group by (Vehicle.SerialNo)
HAVING COUNT(RepairOrder.SerialNo) > 2);
答案 0 :(得分：0)
你可以试试这个
SELECT V.SerialNo, V.Year, V.Make, V.Model , COUNT(R.OrdNo) AS NumberOfRepairs
FROM Vehicle V INNER JOIN RepairOrder R ON V.SerialNo = R.SerialNo
GROUP BY V.SerialNo
HAVING COUNT(R.OrdNo) > 2;