Question

public void actionPerformed(ActionEvent e) {
    String action = e.getActionCommand();
    if(action.equals("Reset")){
        title.setSelectedIndex(0);
        forename.setText(null);
        surname.setText(null);
        age.setText(null);
        contactNo.setText(null);
        houseNo.setText(null);
        streetName.setText(null);
        districtName.setText(null);
        cityName.setText(null);
        postcode.setText(null);
        healthPlan.setSelectedIndex(0);
        treatment.setSelectedIndex(0);  

    }

单击“提交”按钮时，如何使用文本字段中的数据更新sql数据库。到目前为止，我已经编写了这段代码，但是当我点击提交时似乎没有发生任何事情，但是单击它时重置按钮会起作用。

    if(action.equals("Submit")){
        Connection con = null; 
        String db="jdbc:mysql://stusql.dcs.shef.ac.uk/team009?user=team009&password=********";

        try { 

           con = DriverManager.getConnection(db);
           Statement bil = con.createStatement();

           bil.execute("INSERT INTO Patient (ForeName, SurName, DateOfBirth, PhoneNumber, HouseNumber, PostCode) " + 
            "VALUES (forename.getText(),surname.getText,age.getText,contactNo.getText(),houseNo.getText(),postcode.getText())");

           JOptionPane.showMessageDialog(null,"Inserted Successfully!");

        }
        catch (SQLException ex) {
         ex.printStackTrace();
        }
        finally {
         if (con != null)
            try {
                con.close();
            } catch (SQLException e1) {

                e1.printStackTrace();
            }

        }

请任何帮助将不胜感激。

Answer 1

基本上，您当前的查询String

"INSERT INTO Patient (ForeName, SurName, DateOfBirth, PhoneNumber, HouseNumber, PostCode) " + 
        "VALUES (forename.getText(),surname.getText,age.getText,contactNo.getText(),houseNo.getText(),postcode.getText())"

字面上要求数据库插入您提供的文本而不是文本字段中的文本，事实上，数据库应该非常适合这一点并且返回Exception。最好的情况是，它试图找到匹配surname.getText之类的表格/列值，最糟糕的是它正在寻找名为forename.getText()的函数

首先看看：

例如......

try (Connection con = DriverManager.getConnection(null)) {
    try (PreparedStatement stmt = con.prepareStatement("INSERT INTO Patient (ForeName, SurName, DateOfBirth, PhoneNumber, HouseNumber, PostCode) VALUES (?,?,?,?,?,?)")) {
        stmt.setString(1, forename.getText());
        stmt.setString(2, surname.getText());
        stmt.setString(3, age.getText());
        stmt.setString(4, contactNo.getText());
        stmt.setString(5, houseNo.getText());
        stmt.setString(6, postcode.getText());
        // In case you care, you can get the number of rows that were updated...
        int rowsUpdated = stmt.executeUpdate();
    }
} catch (SQLException ex) {
    Logger.getLogger(Test.class.getName()).log(Level.SEVERE, null, ex);
}

您可能会发现The try-with-resources Statement有用......

Answer 2

您没有发送forename，surname等的值，而是发送字符串在java中调用这些值。您需要使用以下代码部分： -

bil.execute("INSERT INTO Patient (ForeName, SurName, DateOfBirth, PhoneNumber, HouseNumber, PostCode) VALUES ("'
    + forename.getText() + "', '"
    + surname.getText() + "', '"
    + age.getText() + "', '"
    + contactNo.getText() + "', '"
    + houseNo.getText() + "', '"
    + postcode.getText() + "')");

如何使用Java更新我的Sql数据库

2 个答案: