Question

如何删除仅包含一个或不包含/的文件中的所有行？例如，file.txt：

This / line contains/ more than / one of the characters/.
This / line contains just one.
This / line/ also has/too many/.

输出结果为：

This / line contains/ more than / one of the characters/.
This / line/ also has/too many/.

我试过了grep ^[^/]*/*[^/]$ file.txt，但这似乎打印了所有内容。

Answer 1

试试这个：

awk -F/ 'NF>2' file

试验：

kent$ (master|✔) echo "This / line contains/ more than / one of the characters/.
dquote> This / line contains just one.
dquote> This / line/ also has/too many/."|awk -F/ 'NF>2'
This / line contains/ more than / one of the characters/.
This / line/ also has/too many/.

Answer 2

你离我太远了：

grep '/.*/' <<.eof
This / line contains/ more than / one of the characters/.
This / line contains just one.
This / line/ also has/too many/.
.eof

结果：

This / line contains/ more than / one of the characters/.
This / line/ also has/too many/.

但我也喜欢Kent的解决方案： - ）

Answer 3

echo "This / line contains/ more than / one of the characters/.
This / line contains just one.
This / line/ also has/too many/." \
| sed -n '\@/.*/@p'

输出

This / line contains/ more than / one of the characters/.
This / line/ also has/too many/.

-n表示默认情况下不打印。 sed中的正则表达式查找具有多个/字符的行并打印它们。

Sed是一个变量工具，可能不喜欢\中的前导\@字符，所以如果收到错误消息，只需使用sed '@/.*@d'

IHTH

Answer 4

另一种方式：

perl -ne '
 chomp;
 if ( ( $n1 = () = $_ =~ /\//g) > 1 ) { 
    print "$_\n";
 }' afile.txt

Answer 5

这是另一个awk版本：

awk 'gsub(/\//,"&")>1' file
This / line contains/ more than / one of the characters/.
This / line/ also has/too many/.

它尝试与自己交换/。 gsub的输出是命中数。

如何删除BASH中包含少于两个/的所有行？

5 个答案: