我有这个代码。但是当我使用查询并且我的国家字符ÆØÅ没有显示时,在json数组中它只是说“NULL”。
我如何解码或改变以便我可以使用这些字符? 当我将内容字符集设置为iso-8859-1时,我获得了国家字符。但正如我发现json编码只使用utf-8编码。那么我怎样才能使用ÆØÅ并让它在json数组中工作?
/*
* Following code will get single utested details
* A utested is identified by utested id (uid)
*/
header('Content-Type: charset=UTF-8');
// array for JSON response
$response = array();
// include db connect class
require_once __DIR__ . '/dbconnect.php';
// connecting to db
$db = new DB_CONNECT();
// check for post data
if (isset($_GET["uid"])) {
$uid = $_GET['uid'];
// get a utested from utesteds table
$result = mysql_query("
SELECT p.uid
, u.name
, u.description
, u.url
, u.picurl
, u.mapurl
, p.price
, ROUND(AVG(r.rating),1) rating
FROM utested u
JOIN price p
ON p.uid = u.uid
JOIN ( SELECT uid, MAX(pid) latest_price FROM price GROUP BY uid ) px
ON px.uid = p.uid
AND px.latest_price = p.pid
JOIN rating r
ON r.uid = u.uid
WHERE u.uid=$uid
ORDER BY u.uid DESC LIMIT 1
") or die(mysql_error());
if (!empty($result)) {
// check for empty result
if (mysql_num_rows($result) > 0) {
$result = mysql_fetch_array($result);
$utested = array();
$utested["uid"] = $result["uid"];
$utested["name"] = $result["name"];
$utested["description"] = $result["description"];
$utested["url"] = $result["url"];
$utested["picurl"] = $result["picurl"];
$utested["mapurl"] = $result["mapurl"];
$utested["price"] = $result["price"];
$utested["rating"] = $result["rating"];
// success
$response["success"] = 1;
// user node
$response["utested"] = array();
array_push($response["utested"], $utested);
//print_r ($response);
// echoing JSON response
echo json_encode($response);
} else {
// no utested found
$response["success"] = 0;
$response["message"] = "No utested found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no utested found
$response["success"] = 0;
$response["message"] = "No utested found";
// echo no users JSON
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
这是我完整的PHP文件。请尝试适应,以便我可以测试它。