SQL Server 2008基于1个唯一列查找行，并在第二列中查找重复项

Question

您能否建议我如何编写查询以检索以下内容？

我需要找到A中的值重复但B中的值不同的任何行

  A    B 
4567    2 
852125  9
444     8
2547    25
255     4
256     1
2547    25
2547    27
259     4
2547    25

应该返回

2547    27 
2547    25 

因为2547在B列中有两个不相同的值

感谢您的期待

P

Answer 1

with cte1 as (
    select distinct A, B from Table1
), cte2 as (
    select A, B, count(*) over(partition by A) as cnt from cte1
)
select
    A, B
from cte2 
where cnt > 1

<强> sql fiddle demo

或

with cte as (
    select distinct
        A, B, min(B) over(partition by A) as m1, max(B) over(partition by A) as m2
    from Table1
)
select
    A, B
from cte
where m1 <> m2

<强> sql fiddle demo

Answer 2

试试这个

With DemoTable  AS
(
          Select 4567   A,2  B
Union All Select 852125  ,9
Union All Select 444     ,8
Union All Select 2547    ,25
Union All Select 255     ,4
Union All Select 256     ,1
Union All Select 2547    ,25
Union All Select 2547    ,27
Union All Select 259     ,4
Union All Select 2547    ,25
)
Select Distinct A, B
From DemoTable  
Where A In
(
    Select A
    From DemoTable
    Group By A
    Having Count (Distinct B) > 1
)

输出

A           B
----------- -----------
2547        25
2547        27

(2 row(s) affected)

Answer 3

只需使用嵌套选择语句，其中一个计数，分组且 声明。

select distinct tbl.A,tbl.B from table_name tbl
 where tbl.A in (select A from (
  select  tb.A, count(tb.B) 
  from table_name tb group by tb.A having count(tb.B)>1)) 
order by tbl.A