Question

我有这些文件：

“id_1_1.php”，“id_1_2.php”，“id_1_3.php”等 “id_2_1.php”，“id_2_2.php”，“id_2_3.php”等

文件数量未知，因为它总是会增长..

所有文件都在同一个目录中..

我想制作一个if语句：

仅在文件名称以“_1”
另一个加载所有以“id_1”

我该怎么做？谢谢！

edit1：不会跳过这些数字，一旦我为id_1_系列产品添加了另一个项目，我会将新的项目添加为id_1_1，id_1_2等等。所以不要跳过..

Answer 1

function my_include($f, $s)
{
    @include_once("id_" . $f . "_" . $s . ".php");
}


function first_function($howmany = 100, $whatstart = '1')
{
    for ($i=1; $i <= $howmany; $i++)
    {
        my_include('1', $i)
    }
}

function second_function($howmany = 100, $whatend = '1')
{
    for ($i=1; $i <= $howmany; $i++)
    {
        my_include($i, '1');
    }
}

Answer 2

基于Svisstack的原始答案（未经测试）：

function doIncludes($pre='',$post=''){
    for ($i=1;1;$i++)
        if (file_exists($str=$pre.$i.$post.'.php'))
            include($str);
        else
            return;
}

function first_function(){
    doIncludes('id_','_1');
}

function second_function(){
    doIncludes('id_1_');
}

Answer 3

这将解析每个递增1的文件，直到找到不存在的文件。假设连续数字，它应该捕获每个现有文件。如果您想在名称中包含除1以外的数字的文件，只需根据需要更改$ lookingfor。

$lookingfor = 1;
$firstnum=1;
while ($firstnum>0) {
$secondnum=1;
  while ($secondnum>0) {
    $tempfilename = "id_".$firstnum."_".$secondnum.".php";
    if file_exists($tempfilename) {
      if (($firstnum==$lookingfor)||($secondnum==$lookingfor)) {include $tempfilename; }
      $secondnum++;
    } else {
    $secondnum=-1;
    }
  }
$firstnum++;
}

Answer 4

// Each of these:
//   - scans the directory for all files
//   - checks each file
//   - for each file, does it match the pattern described
//   - if it does, expand the path
//   - include the file once

function includeFilesBeginningWith($dir, $str) {
    $files = scandir($dir);
    foreach ($files as $file) {
        if (strpos($file, $str) === 0) {
            $path = $dir . '/' . $file;
            include_once($path);
        }
    }
}

function includeFilesEndingWith($dir, $str) {
    $files = scandir($dir);
    foreach ($files as $file) {
        if (strpos(strrev($file), strrev($str)) === 0) {
            $path = $dir . '/' . $file;
            include_once($path);
        }
    }
}

/* To use: - the first parameter is ".",
   the current directory, you may want to
   change this */
includeFilesBeginningWith('.', 'id_1');
includeFilesEndingWith('.', '_1.php');

PHP帮助“if”语句动态包含文件

4 个答案: