this.reportTextBox.Text += String.Join(Environment.NewLine, notEqualValue);
此代码行将打印出此列表中的所有元组值。它将显示如下:
(02/12/14 00:00:00,你好)
我只希望显示DateTime方法的Date函数。所以看起来应该是这样的:
(02/12/14,你好)
这可能吗?
元组的初始化可以在下面看到。
Tuple<DateTime, string> a = new Tuple<DateTime, string>(data_entryA.Date, tag_a_name);
答案 0 :(得分:1)
确定您可以格式化日期
var values = notEqualValue.Select(x => string.Join(",",x.Item1.ToString("d"),x.Item2));
this.reportTextBox.Text += String.Join(Environment.NewLine, values);
"d"
format specifier以格式6/15/2009
为您提供日期,但文化敏感。因此,如果您有不同的文化,请尝试使用DateTime.ParseExact
方法和custom format string。
答案 1 :(得分:0)
使用单字符格式 字符类型
您可以使用带有ToString或DateTime.ParseExact的单个char来指定预设格式。这些是标准格式,在许多程序中都很有用。它们可以消除自定义格式字符串中的拼写错误。 DateTime.Parse
class Program
{
static void Main()
{
DateTime now = DateTime.Now;
Console.WriteLine(now.ToString("d"));
Console.WriteLine(now.ToString("D"));
Console.WriteLine(now.ToString("f"));
Console.WriteLine(now.ToString("F"));
Console.WriteLine(now.ToString("g"));
Console.WriteLine(now.ToString("G"));
Console.WriteLine(now.ToString("m"));
Console.WriteLine(now.ToString("M"));
Console.WriteLine(now.ToString("o"));
Console.WriteLine(now.ToString("O"));
Console.WriteLine(now.ToString("s"));
Console.WriteLine(now.ToString("t"));
Console.WriteLine(now.ToString("T"));
Console.WriteLine(now.ToString("u"));
Console.WriteLine(now.ToString("U"));
Console.WriteLine(now.ToString("y"));
Console.WriteLine(now.ToString("Y"));
}
}
输出
d 2/27/2009
D Friday, February 27, 2009
f Friday, February 27, 2009 12:11 PM
F Friday, February 27, 2009 12:12:22 PM
g 2/27/2009 12:12 PM
G 2/27/2009 12:12:22 PM
m February 27
M February 27
o 2009-02-27T12:12:22.1020000-08:00
O 2009-02-27T12:12:22.1020000-08:00
s 2009-02-27T12:12:22
t 12:12 PM
T 12:12:22 PM
u 2009-02-27 12:12:22Z
U Friday, February 27, 2009 8:12:22 PM
y February, 2009
Y February, 2009
所以最后你应该尝试
DateTime now = DateTime.Now;
Console.WriteLine(now.ToString("d"));