创建一种更简单的嵌套函数方法

时间:2014-12-02 09:13:37

标签: javascript node.js function underscore.js nested

我希望降低像这样的代码的开销

foo(bar(baz("hello"))) // function hell

理想情况下是这样的

var fbb = bind(foo, bar, baz)
foo("hello")

这是否存在?原生或图书馆?

我浏览了underscorebind

3 个答案:

答案 0 :(得分:1)

function getCaller(first) {
    var rest = Array.prototype.slice.call(arguments, 1);
    return function (value) {
        return rest.reduce(function (previous, next) {
            return next(previous);
        }, first(value));
    };
}

function foo(string) {
    return string + ' world!';
}

function bar(string) {
    return string + ' Hi';
}

function baz(string) {
    return string + ' Mom!';
}

var caller = getCaller(foo, bar, baz);
console.log(caller('Hello'));
// Prints: Hello world! Hi Mom!

答案 1 :(得分:1)

Underscore有compose功能可以做你想做的事情:

var composite = _.compose(foo, bar, baz);

composite('hello');



function foo(a1){
  return 'foo' + a1;
}		

function bar(a2){
  return 'bar' + a2;
}

function baz(a3){
  return 'baz' + a3;
}

alert(foo(bar(baz("hello"))));

var composite = _.compose(foo, bar, baz);

alert( composite('hello') );

<script src="//cdnjs.cloudflare.com/ajax/libs/underscore.js/1.7.0/underscore-min.js"></script>
&#13;
&#13;
&#13;

答案 2 :(得分:0)

var bind = function() {
  var fns = Array.prototype.slice.call(arguments).reverse();
  return function(value) {
    for (var key in fns) {
      var fn = fns[key];
      console.log(fn);
      value = fn(value);
    }
    return value;
  }
}

function plusTomato(value) {
  return value + "tomato";
}

function plusPear(value) {
  return value + "pear";
}

var plus = bind(plusTomato, plusPear);

var y = plus("pancake"); //pankaketomatopear
console.log(y);
var x = plusTomato(plusPear("pancake")); //pankaketomatopear
console.log(x);