所以我试图使用PBKDF2来获得一个给定256位256位字符串的密钥。我能够使用C#的Rfc2898DeriveBytes和node-crypto的pbkdf2来获得相同的密钥,但是,对于C ++我不能说同样的。我不确定我是否进行了错误的转换或使用不正确的功能,但我会让你们看看它。
C ++
/* 256bit key */
string key = "Y1Mjycd0+O+AendY5pB58JMlmS0EmBWgjdj2r2KW6qQ=";
string decodedKey;
StringSource(key, true, new Base64Decoder(new StringSink(decodedKey)));
const byte* keyByte = (const byte*) decodedKey.data();
/* Generate IV */
/*
AutoSeededRandomPool prng;
byte iv[AES::BLOCKSIZE];
prng.GenerateBlock(iv, sizeof(iv));
*/
/* FOR TESTING PURPOSES, HARDCODE IV */
string iv = "5iFv54dCRq5icQbD7QHQzg==";
string decodedIv;
StringSource(iv, true, new Base64Decoder(new StringSink(decodedIv)));
const byte* ivByte = (const byte *) decodedIv.data();
byte derivedKey[32];
PKCS5_PBKDF2_HMAC<CryptoPP::SHA1> pbkdf2;
pbkdf2.DeriveKey(derivedKey, 32, 0, keyByte, 32, ivByte, 16, 100);
/*
* derivedKey: 9tRyXCoQLTbUOLqm3M4OPGT6N25g+o0K090fVp/hflk=
*/
C#
// string key = "Y1Mjycd0+O+AendY5pB58JMlmS0EmBWgjdj2r2KW6qQ="; // need to convert it to byte data
string key = Convert.FromBase64String("Y1Mjycd0+O+AendY5pB58JMlmS0EmBWgjdj2r2KW6qQ="); // change above to this
RijndaelManaged symKey = new RijndaelManaged();
symKey.GenerateIV(); /* Assume hardcoded IV same as above */
Rfc2898DeriveBytes derivedKey = new Rfc2898DeriveBytes (key, symKey.IV, 100);
/*
* derivedKey: dZqBpZKyUPKn8pU4pyyeAw7Rg8uYd6yyj3WI1MIJSyc=
*/
JS
// var key = "Y1Mjycd0+O+AendY5pB58JMlmS0EmBWgjdj2r2KW6qQ="; // need to convert it to byte data
var key = new Buffer("Y1Mjycd0+O+AendY5pB58JMlmS0EmBWgjdj2r2KW6qQ=", "base64"); // changed above to this
var iv = crypto.randomBytes(16);
iv = "5iFv54dCRq5icQbD7QHQzg=="; /* HARDCODE IV */
crypto.pbkdf2(key, iv, 100, 32, function(err, derivedKey) { }
/*
* derivedKey: dZqBpZKyUPKn8pU4pyyeAw7Rg8uYd6yyj3WI1MIJSyc=
*/
主要的问题是,我在C ++的CryptoPP上做错了什么 库,它没有得到相同的值。
解决方案:我是愚蠢的......经过审核后我意识到我在JavaScript和C#上的原始实现我错过了一个关键步骤,由于某些原因我没有得到编译器的抱怨。基本上问题是我在C#和JS实现的算法之前没有将用于转换为字节数据的密钥...
无论如何,建议的解决方案是:不要在凌晨4点编码并确保数据转换保持一致......
我猜TL; DR就是C#和JS将我的256位密钥转换为字节数据而不是base64转换。
答案 0 :(得分:3)
主要的问题是,我在C ++的CryptoPP库上做错了什么,它没有得到相同的值。
好吧,我不认为你在C ++中使用Crypto ++和PBKDF2做错了什么。我认为其他库正在以不同的方式设置参数,或者它们有点不标准。
我能够使用Crypto ++到达IETF的test vectors for PBKDF2:
// From https://www.ietf.org/rfc/rfc6070.txt
// PKCS #5: Password-Based Key Derivation Function 2 (PBKDF2) Test Vectors
//
// Input:
// P = "password" (8 octets)
// S = "salt" (4 octets)
// c = 1
// dkLen = 20
//
// Output:
// DK = 0c 60 c8 0f 96 1f 0e 71
// f3 a9 b5 24 af 60 12 06
// 2f e0 37 a6 (20 octets)
int main(int argc, char* argv[])
{
byte password[] ="password";
size_t plen = strlen((const char*)password);
byte salt[] = "salt";
size_t slen = strlen((const char*)salt);
int c = 1;
byte derived[20];
PKCS5_PBKDF2_HMAC<CryptoPP::SHA1> pbkdf2;
pbkdf2.DeriveKey(derived, sizeof(derived), 0, password, plen, salt, slen, c);
string result;
HexEncoder encoder(new StringSink(result));
encoder.Put(derived, sizeof(derived));
encoder.MessageEnd();
cout << "Derived: " << result << endl;
return 0;
}
该程序的运行:
$ ./cryptopp-test.exe
Derived: 0C60C80F961F0E71F3A9B524AF6012062FE037A6
我认为你应该做的第一件事是验证C#和Javascript实现使用与Crypto ++和IETF相同的字符编码。
如果不是这样,那么检查C#和Javascript是否使用目的字节。 Crypto ++没有,你可以在pwdbased.h看到实现。
不幸的是,当我拨入你的参数时,我得到了一些不同的东西:
int main(int argc, char* argv[])
{
string t1 = "Y1Mjycd0+O+AendY5pB58JMlmS0EmBWgjdj2r2KW6qQ=";
string t2 = "5iFv54dCRq5icQbD7QHQzg==";
string pw, iv;
Base64Decoder b1(new StringSink(pw));
b1.Put((const byte*)t1.data(), t1.size());
b1.MessageEnd();
Base64Decoder b2(new StringSink(iv));
b2.Put((const byte*)t2.data(), t2.size());
b2.MessageEnd();
int c = 100;
byte derived[32];
cout << "pw size: " << pw.size() << endl;
cout << "iv size: " << iv.size() << endl;
PKCS5_PBKDF2_HMAC<CryptoPP::SHA1> pbkdf2;
pbkdf2.DeriveKey(derived, sizeof(derived), 0, (byte*)pw.data(), pw.size(), (byte*)iv.data(), iv.size(), c);
string result;
HexEncoder encoder(new StringSink(result));
encoder.Put(derived, sizeof(derived));
encoder.MessageEnd();
cout << "Derived: " << result << endl;
return 0;
}
运行结果为:
$ ./cryptopp-test.exe
pw size: 32
iv size: 16
Derived: F6D4725C2A102D36D438BAA6DCCE0E3C64FA376E60FA8D0AD3DD1F569FE17E59