MYSQL-在循环结束日期时显示数据

时间：2014-12-02 07:18:14

标签： php mysql codeigniter

在过去一个月中，我一直在创建一个基准系统，允许用户添加类别＆amp;基准项，在特定年份内每周保留数据。我在创建一个mysql语句时遇到了问题，该语句显示每个基准测试项及其在yr内所有周的结果，即使该周没有数据或没有年份数据。以下是我一直在测试的查询和表格列。我正在使用codeigniter并计划以底部映射的格式显示结果。我为这个冗长的描述道歉，但我试图尽可能清楚。任何帮助将不胜感激。

tblbenchmarkitem
=================
itemID | itemDescription | itemTarget | ItemFreq | FKcategoryID

tblbenchmarkData
================
dataID | FKitemID | resultDate | result | dateAdded | dateModified

tblcategories
===============
categoryID | categoryName | parentID | FKdeptID

tblcalendardates  - stores 52 weeks for year Saturday to Friday
================
id | year | startDate | endDate

这些是我在模型中的mysql语句。我将在年份的函数参数中设置一个默认值。

public function get_data() {
    $dates = $this->db->query("SELECT endDate FROM tblcalendardates WHERE year = '2014' ORDER BY endDate");
    $dates = $dates->result();
    foreach ($dates as $date ) {
        //$query = "SELECT tblcalendardates.enddate, tblbenchmarkitems.itemDescription, tblbenchmarkitems.itemTarget, tblbenchmarkitems.itemFrequency, tblbenchmarkdata.resultDate, IFNULL(tblbenchmarkdata.result,0) AS result, (SELECT strCategoryName FROM tblcategories WHERE tblbenchmarkitems.FKcategoryID = tblcategories.categoryID) AS category FROM tblbenchmarkdata LEFT JOIN tblbenchmarkitems ON tblbenchmarkdata.FKitemID = tblbenchmarkitems.itemID JOIN tblcalendardates WHERE DATE(tblbenchmarkdata.resultDate) BETWEEN (SELECT MIN(DATE(tblcalendardates.startdate)) FROM tblcalendardates WHERE tblcalendardates.year = " . date('Y') . ") AND (SELECT MAX(DATE(tblcalendardates.enddate)) FROM tblcalendardates WHERE tblcalendardates.year = " . date('Y') . ") GROUP BY category ORDER BY tblcalendardates.enddate";
        $query = 'SELECT c.*, i.itemDescription, i.itemTarget, IFNULL(d.result, 0) as result,"' . $date ->endDate . '" FROM tblcategories AS c JOIN tblbenchmarkitems AS i ON i.FKcategoryID = c.categoryID JOIN tblbenchmarkdata as d ON i.itemID = d.FKitemID JOIN tblcalendardates WHERE DATE(d.resultDate) BETWEEN (SELECT MIN(DATE(tblcalendardates.startdate)) FROM tblcalendardates WHERE tblcalendardates.year = "' . date('Y') . '") AND (SELECT MAX(DATE(tblcalendardates.enddate)) FROM tblcalendardates WHERE tblcalendardates.year = "' . date('Y') . '") GROUP BY strCategoryName';
        $query = $this->db->query($query);

    return $query->result();
    }
}

这是我认为的

<table class="table table-hover data-list">
    <thead>
        <tr>
          <th class="th-set-width1">Benchmark Item</th>
          <th class="th-set-width2">Target</th>
        <?php foreach( $weeks as $week ): ?>
          <th class="th-set-width2"><?php echo date('m-d-Y', strtotime($week->enddate)); ?></th>
        <?php endforeach; ?>
        </tr>
    </thead>
    <tbody>
        <?php foreach( $entries as $entry ) : ?>
        <tr>
          <td><?php echo $entry->itemDescription; ?></td>
          <td><?php echo $entry->itemTarget; ?></td>
          <?php for ($i = 0; $i < 52; $i++) : ?>
            <?php if ($entry->result != NULL || $entry->result > 0): ?>
              <td><?php echo $entry->result; ?></td>
            <?php else: ?>
              <td>0</td>
            <?php endif; ?>
          <?php endfor; ?>
        </tr>
        <?php endforeach; ?>
    </tbody>
</table>

这就是我想在表格中显示数据的方式。

-----------------------------------------------------------------------------------
categoryName
====================================================================================
itemDescription |  itemTarget | 01-03-14 | 01-10-14 | 01-17-14 | 01-24-14 | 01-31-14
=====================================================================================
No. of Visits   |    12.00    |   NULL   |   NULL   |   15.00  |    NULL  |   20.00 
No. of Calls    |    17.00    |   12.00  |   NULL   |   17.00  |    22.00 |   NULL

2 个答案:

答案 0 :(得分：0)

我在代码中添加了一些更改，几乎产生了我正在寻找的响应。现在唯一的问题是我有两个项目，每个项目都有一个结果。

我的模特：

public function get_data() {
    $items = $this->db->query('SELECT * FROM tblbenchmarkitems');
    $items = $items->result();
    foreach ( $items as $item ) {
        $query = 'SELECT c.endDate, IFNULL(d.result,0) as result FROM tblbenchmarkdata AS d RIGHT JOIN tblcalendardates as c ON (DATE(d.resultDate) = c.endDate) JOIN tblbenchmarkitems as i  WHERE c.year = "2014" AND i.itemID = "' . $item->itemID .'" GROUP BY c.endDate';
        $query = $this->db->query($query);
        $data[] = array(
            'itemID'            => $item->itemID,
            'itemDescription'   => $item->itemDescription,
            'itemTarget'        => $item->itemTarget,
            'dates'             => $query->result()
        );
    }
    return $data;
}

我的观点：

<table class="table table-hover data-list">
  <thead>
    <tr>
      <th class="th-set-width1">Benchmark Item</th>
      <th class="th-set-width2">Target</th>
    <?php foreach( $weeks as $week ): ?>
       <th class="th-set-width2"><?php echo date('m-d-Y', strtotime($week->enddate)); ?></th>
    <?php endforeach; ?>
    </tr>
  </thead>

  <tbody>

  <?php for( $n = 0; $n < count($entries); $n++ ) : ?>

    <tr>
      <td><?php echo $entries[$n]['itemDescription']; ?></td>
      <td><?php echo $entries[$n]['itemTarget']; ?></td>
      <?php for( $i = 0; $i < count($entries[$n]['dates']);  $i++) :?>
      <td><?php echo $entries[$n]['dates'][$i]->result; ?></td>
      <?php endfor; ?>
    </tr>

  <?php endfor; ?>

  </tbody>

</table>

查询结果中的表格格式 - 问题是记录1和记录2是否显示两个结果。记录1在11/7/14记录结果，记录2记录在2014年7月11日

：

+-----------------------------------------+--------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+
|Benchmark Item                           | Target |01-03-2014|01-10-2014|01-17-2014|01-24-2014|01-31-2014|02-07-2014|02-14-2014|02-21-2014|02-28-2014|03-07-2014|03-14-2014|03-21-2014|03-28-2014|04-04-2014|04-11-2014|04-18-2014|04-25-2014|05-02-2014|05-09-2014|05-16-2014|05-23-2014|05-30-2014|06-06-2014|06-13-2014|06-20-2014|06-27-2014|07-04-2014|07-11-2014|07-18-2014|07-25-2014|08-01-2014|08-08-2014|08-15-2014|08-22-2014|08-29-2014|09-05-2014|09-12-2014|09-19-2014|09-26-2014|10-03-2014|10-10-2014|10-17-2014|10-24-2014|10-31-2014|11-07-2014|11-14-2014|11-21-2014|11-28-2014|12-05-2014|12-12-2014|12-19-2014|12-26-2014|
+-----------------------------------------+--------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+
|Total No. of Calls Conducted               17.00     0.00        0.00        0.00      0.00        0.00       0.00     0.00        0.00        0.00        0.00        0.00        0.00      0.00      0.00       0.00     0.00        0.00        0.00        0.00        0.00        0.00      0.00     0.00    0.00     0.00        0.00        0.00        **2.00**        0.00        0.00      0.00     0.00    0.00     0.00        0.00        0.00        0.00        0.00        0.00      0.00        0.00     0.00         0.00       0.00   **12.00**     0.00        0.00        0.00     0.00      0.00      0.00       0.00   |
+-----------------------------------------+--------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+
|Total No. of Random Visits                 29.00     0.00        0.00        0.00      0.00        0.00       0.00     0.00        0.00        0.00        0.00        0.00        0.00      0.00      0.00       0.00     0.00        0.00        0.00        0.00        0.00        0.00      0.00     0.00    0.00     0.00        0.00        0.00        **2.00**        0.00        0.00      0.00     0.00    0.00     0.00        0.00        0.00        0.00        0.00        0.00      0.00        0.00     0.00         0.00       0.00   **12.00**     0.00        0.00        0.00     0.00      0.00      0.00       0.00   |
+-----------------------------------------+--------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+----------+

答案 1 :(得分：0)

<强>解决

在模型中，我将删除了连接的查询更改为 tblbenchmarkitems 表，并删除了在where语句中指定 itemID 的需要。我将 FKitemID 字段添加到输出中以帮助确保结果对应于正在评估的特定项目（即，如果项目ID为1并且数组中提供的结果属于ID为1的项目，然后仅显示ID 1的数据。）

模型中获取基准数据的功能。

public function get_data() {
    $items = $this->db->query('SELECT * FROM tblbenchmarkitems');
    $items = $items->result();
    foreach ( $items as $item ) {
        $query = 'SELECT c.endDate as weekending, IFNULL(d.result,0) as result, d.FKitemID FROM tblbenchmarkdata AS d RIGHT JOIN tblcalendardates as c ON (DATE(d.resultDate) = c.endDate) WHERE c.year = "2014" GROUP BY weekending';
        $query = $this->db->query($query);
        $data[] = array(
            'itemID'            => $item->itemID,
            'itemDescription'   => $item->itemDescription,
            'itemTarget'        => $item->itemTarget,
            'dates'             => $query->result()
        );
    }
    return $data;
}

视图：

<table class="table table-hover data-list">
  <thead>
     <tr>
       <th class="th-set-width1">Benchmark Item</th>
       <th class="th-set-width2">Target</th>

    <?php foreach( $weeks as $week ): ?>
        <th class="th-set-width2"><?php echo date('m-d-Y', strtotime($week->enddate)); ?></th>
    <?php endforeach; ?>

     </tr>
  </thead>

  <tbody>

  <?php for( $n = 0; $n < count($entries); $n++ ) : ?>
    <tr>
      <td><?php echo $entries[$n]['itemDescription']; ?></td>
      <td><?php echo $entries[$n]['itemTarget']; ?></td>

     <?php for( $i = 0; $i < count($entries[$n]['dates']);  $i++) :?>
       <?php if ( $entries[$n]['itemID'] == $entries[$n]['dates'][$i]->FKitemID ) : ?>

       <td><?php echo $entries[$n]['dates'][$i]->result; ?></td>

       <?php else: ?>

       <td>0.00</td>

       <?php endif; ?>
     <?php endfor; ?>

   </tr>
  <?php endfor; ?>

  </tbody>
</table>

最后，在视图中，我在第二个 for循环之后添加了一个if语句（在整个周内输出数据的那个）。它会检查是否有输出项目ID的结果，如果有，则只显示行和＆amp;它对应的列。如果没有，则显示＆＃34; 0.00＆＃34;。

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