Question

下面的代码在验证期间给出了以下错误。这是否意味着我无法在complexType元素中嵌套simpleType元素？

Error - Line 18, 17: org.xml.sax.SAXParseException; lineNumber: 18; columnNumber: 17; s4s-elt-must-match.1: The content of 'sequence' must match (annotation?, (element | group | choice | sequence | any)*). A problem was found starting at: simpleType.

<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema" 
    targetNamespace="http://www.example.org/carType"
    elementFormDefault="qualified">

    <element name="carType">
        <complexType>
            <sequence>
                <simpleType name="colour">
                    <restriction base="string">
                        <enumeration value="blue" />
                        <enumeration value="yellow" />
                        <enumeration value="green" />
                        <enumeration value="black" />
                        <enumeration value="white" />
                    </restriction>
                </simpleType>
                <simpleType name="body">
                    <restriction base="string">
                        <enumeration value="sedan" />
                        <enumeration value="hatchback" />
                    </restriction>
                </simpleType>
            </sequence>
        </complexType>
    </element>
</schema>

Answer 1

你很亲密。只需对您的XSD进行两次小调整：

你有<simpleType name="colour">的地方，而是声明一个 colour元素：
```
    <element name="colour">
      <simpleType>
```
同样，你有<simpleType name="body">的地方声明body元素：
```
    <element name="body">
      <simpleType>
```

然后：

<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema" 
        targetNamespace="http://www.example.org/carType"
        elementFormDefault="qualified">
  <element name="carType">
    <complexType>
      <sequence>
        <element name="colour">
          <simpleType>
            <restriction base="string">
              <enumeration value="blue" />
              <enumeration value="yellow" />
              <enumeration value="green" />
              <enumeration value="black" />
              <enumeration value="white" />
            </restriction>
          </simpleType>
        </element>
        <element name="body">
          <simpleType>
            <restriction base="string">
              <enumeration value="sedan" />
              <enumeration value="hatchback" />
            </restriction>
          </simpleType>
        </element>
      </sequence>
    </complexType>
  </element>
</schema>

在SimpleType中嵌套simpleType

1 个答案: