我有一个包含按钮的JDesktopPane。当我点击它时,我想出现一个自定义的JOptionPane,其中我添加了一个JLabel和一个JTable。
问题是我在JOptionPane
中没有得到任何东西这是我的代码:
class Viewer extends JPanel{
public Viewer(){
JLabel l = new JLabel("Hi");
JTable t = new JTable(2,2);
JPanel p = new JPanel();
p.add(l,BorderLayout.NORTH);
p.add(t,BorderLayout.CENTER);
}
}
public class JOptionPanesWithJPanel extends JFrame{
JPanel desktoppane;
public JOptionPanesWithJPanel(){
desktoppane = new JPanel();
int inset = 50;
Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
setBounds(inset, inset, screenSize.width - inset*2, screenSize.height - inset*2);
JPanel butPanel = new JPanel();
JButton but = new JButton("click");
butPanel.setVisible(true);
butPanel.add(but);
desktoppane.add(butPanel);
getContentPane().add(desktoppane, BorderLayout.CENTER);
setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
setVisible(true);
but.addActionListener(new ActionListener(){
@Override
public void actionPerformed(ActionEvent ae) {
Viewer v = new Viewer();
//make JOptionPane resisable
UIManager.put("OptionPane.minimumSize",new Dimension(150,150));
JOptionPane.showMessageDialog(null, v, null, JOptionPane.PLAIN_MESSAGE);
}
});
}
public static void main(String[] args) {
for(javax.swing.UIManager.LookAndFeelInfo lookAndFeelInfo : javax.swing.UIManager.getInstalledLookAndFeels()){
if("Windows".equals(lookAndFeelInfo.getName())){
try {
javax.swing.UIManager.setLookAndFeel(lookAndFeelInfo.getClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
System.out.println(ex);
}
break;
}
}
JOptionPanesWithJPanel j = new JOptionPanesWithJPanel();
}
}
我应该怎么做才能在JOptionPane中显示面板?提前谢谢。
PS: 我使用JoptionPane的原因是禁止用户点击JDesktopPane中的任何其他位置(以及按钮),除非他关闭当前窗口。
答案 0 :(得分:2)
您已将组件添加到第二个面板,但未将面板添加到Viewer
...
public Viewer() {
JLabel l = new JLabel("Hi");
JTable t = new JTable(2, 2);
JPanel p = new JPanel(); // <-- Create the new panel
p.add(l, BorderLayout.NORTH);
p.add(t, BorderLayout.CENTER);
// And now what??
}
如果没有更多证据,我会抛弃第二个面板,直接将组件添加到Viewer
...
public Viewer() {
setLayout(new BorderLayout());
JLabel l = new JLabel("Hi");
JTable t = new JTable(2, 2);
add(l, BorderLayout.NORTH);
add(t, BorderLayout.CENTER);
}
Nit挑选......
此...
Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
setBounds(inset, inset, screenSize.width - inset * 2, screenSize.height - inset * 2);
确定框架大小/位置的方法真的很差。不是每个人都有任务栏/码头相同的大小或相同的位置,你不应该依赖&#34;魔术&#34;数字(你编号的数字),相反,你应该找到适当的决定当前的环境状态。
有关检测屏幕尺寸和屏幕可视区域的详细信息,请参阅How to set present screensize in Java Swing?