我无法弄清楚为什么DateTime::diff
的年份(y)不起作用。
这就是我所拥有的
$startDate = new DateTime('2009-12-01');
$endDate = new DateTime('2014-12-01');
// $current = $workid->current;
if($current) // currently works at this job
{
// $endDate = new DateTime(); // current date/time
}
$diff = $endDate->diff($startDate);
if($diff->y = 0)
{
if($diff->m > 1)
{
$string = $diff->m . ' months';
}
else
{
$string = '1 month';
}
}
elseif ($diff->y = 1)
{
if($diff->m > 1)
{
$string = '1 year ' . $diff->m . ' months';
}
else
{
$string = '1 year 1 month';
}
}
else
{
if($diff->m > 1)
{
$string = $diff->y . ' years ' . $diff->m . ' months';
}
else
{
$string = $diff->y . ' years 1 month';
}
}
print_r($diff);
输出
DateInterval Object ( [y] => 1 [m] => 0 [d] => 0 [h] => 0 [i] => 0 [s] => 0 [weekday] => 0 [weekday_behavior] => 0 [first_last_day_of] => 0 [invert] => 1 [days] => 1826 [special_type] => 0 [special_amount] => 0 [have_weekday_relative] => 0 [have_special_relative] => 0 )
[y]
应该说5
,但无论我将1
年更改为哪一年,它都会显示$startDate
。
这是我的php -v
输出
PHP 5.5.9-1ubuntu4.5 (cli) (built: Oct 29 2014 11:59:10)
Copyright (c) 1997-2014 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies
with Zend OPcache v7.0.3, Copyright (c) 1999-2014, by Zend Technologies
答案 0 :(得分:1)
将条件中的=
更改为==
(全部)
否则你做了一个作业,最后一个作为$diff->y = 1
,这就是输出为1的原因!
您必须将其更改为:$diff->y == 1
所以它与此值进行比较
有关比较运算符的更多信息,请查看:http://php.net/manual/en/language.operators.comparison.php