Question

<form action="results.php" name="Search" method="post">
    <label>Search by Last Name:</label> <input class="inputbox" type="text" name='lastname'>
    <input class="button" type="submit" value="Search" name="lastnamesearch" />
</form><?php
$conn = oci_connect ('TBEETS', '********', 'oradev');

$curs = oci_new_cursor($conn);

$sql = "begin :output :=TBEETS.USER_PKG.SELECT_LAST_NAME(:VAR_LAST_NAME); end;";    
$stmt = oci_parse($conn, $sql);
$LAST_NAME="BEETS";
oci_bind_by_name($stmt, ":output", $curs, -1, OCI_B_CURSOR);
oci_bind_by_name($stmt, ":VAR_LAST_NAME", $LAST_NAME);    
oci_execute($stmt); 
oci_execute($curs);
while ($row = oci_fetch_array($curs, OCI_ASSOC + OCI_RETURN_NULLS)){
    $output[] = $row;
}

oci_free_statement($stmt);
oci_free_cursor($curs);

oci_close($conn);

我需要help.php的帮助来显示一个包含正在搜索的姓氏的行。不确定如何获得＆＃39;姓氏＆＃39;匹配变量LAST_NAME

Answer 1

在results.php中，您可以使用以下内容检索姓氏：

$lastname = $_POST['lastname'];

要将其显示在一行中，只需将其附加到HTML输出中：

...
echo "<tr><td>$lastname</td></tr>";
...

Answer 2

在results.php中，您可以使用$_POST方法

获取数据

$lname = $_POST['lastname'];

$sql = "select * from tb_name where col_name = '".$lname."' ";
$result = mysql_query($sql);
while($row = mysql_fetch_array$result()) {
  $id = $row['col_name'];
  //echo your data with 
}

如何显示阵列中的搜索结果？

2 个答案: