Question

以下代码可以很好地将我从URL / JSON文件获取的NSData转换为NSString， EXCEPTION MADE ，因为数据包含换行符

我的代码出了什么问题？

我的代码：

NSError  *errorColetar = nil;
NSURL    *aColetarUrl = [[NSURL alloc]initWithString:@"http://marcosdegni.com.br/petsistema/teste/aColetar3.php"];
NSString *aColetarString = [NSString stringWithContentsOfURL:aColetarUrl encoding:NSUTF8StringEncoding error:&errorColetar];

NSLog(@"NSString: %@", aColetarString);

if (!errorColetar) {
    NSData *aColetarData = [aColetarString dataUsingEncoding:NSUTF8StringEncoding];
    self.arrayAColetar = [NSJSONSerialization JSONObjectWithData:aColetarData options:kNilOptions error:nil];
}
NSLog(@"arrayAColetar %@", self.arrayAColetar);

记录结果：

**NSString**: [{"id_atendimento":"2","observacoes":"ABC-Enter-->
DEF-Enter-->
GFH-END"},{"id_atendimento":"1","observacoes":"123Enter-->
345Enter-->
678End"}]

**arrayAColetar** (null)

正如您所看到的，我的底线是一个空数组:(

提前致谢！

Answer 1

通过检查隐藏在＆＃39;错误：nil＆＃39;之下的错误消息我找到了一个＆＃34;未转义的控制角色围绕着角色＆＃34;从Unescaped control characters in NSJSONSerialization发出并实施以下代码得到一个新的＆＃39;清洁＆＃39;字符串。

- (NSString *)stringByRemovingControlCharacters: (NSString *)inputString { 

NSCharacterSet *controlChars = [NSCharacterSet controlCharacterSet]; 
NSRange range = [inputString rangeOfCharacterFromSet:controlChars]; 
if (range.location != NSNotFound) { 
    NSMutableString *mutable = [NSMutableString stringWithString:inputString]; 
    while (range.location != NSNotFound) { 
        [mutable deleteCharactersInRange:range]; 
        range = [mutable rangeOfCharacterFromSet:controlChars]; 
    } 
    return mutable; 
} 
return inputString;

}

如何将包含换行符的NSData转换为NSString

1 个答案: