我正在学习Java并且正在制作能够改变便士的代码。但是,它完成了,我不确定为while循环输入什么。我会使用while(!change.equals("END"))
但是这不能完成,因为更改是一个整数,所以我该怎么办?
class Main {
public static void main(String args[]) {
System.out.print("#Please enter the amount of change : ");
int change = BIO.getInt();
if (change <= 500 && change >= 1) {
System.out.print("Amount" + "\t" + "Coins" + "\n");
}
while (change =) {
int twopounds, pounds, fifty, twenty, ten, five, two, one;
twopounds = change / 200;
int left = change % 200;
pounds = left / 100;
left = left % 100;
fifty = left / 50;
left = left % 50;
twenty = left / 20;
left = left % 20;
ten = left / 10;
left = left % 10;
five = left / 5;
left = left % 5;
two = left / 2;
left = left % 2;
one = left / 1;
int nbCoins = twopounds + pounds + fifty + twenty + ten + five + two + one;
if (change > 500 || change < 1) {
System.out.print("Invalid amount " + change + "p" + "\n");
}
if (change <= 500 && change >= 1) {
if (nbCoins == 1) {
System.out.print(change + "p " + "\t" + nbCoins + " coin ");
} else {
System.out.print(change + "p " + "\t" + nbCoins + " coins ");
}
if (twopounds > 0) {
System.out.print(twopounds > 1 ? twopounds + "*200p " : "200p ");
}
if (pounds > 0) {
System.out.print(pounds > 1 ? pounds + "*100p " : "100p ");
}
if (fifty > 0) {
System.out.print(fifty > 1 ? fifty + "*50p " : "50p ");
}
if (twenty > 0) {
System.out.print(twenty > 1 ? twenty + "*20p " : "20p ");
}
if (ten > 0) {
System.out.print(ten > 1 ? ten + "*10p " : "10p ");
}
if (five > 0) {
System.out.print(five > 1 ? five + "*5p " : "5p ");
}
if (two > 0) {
System.out.print(two > 1 ? two + "*2p " : "2p ");
}
if (one > 0) {
System.out.print(one > 1 ? one + "*1p " : "1p ");
}
System.out.print("\n");
}
System.out.print("#Please enter the amount of change : ");
change = BIO.getInt();
}
}
}
谢谢:)
答案 0 :(得分:1)
这取决于BIO是什么。通常,如果它是Enumerable,则有.hasNextToken()等选项。但是,在不知道该变量被声明为什么的情况下,我无法告诉您触发器的内容。
答案 1 :(得分:0)
也许这会奏效:
boolean flag = true;
while(flag){
//do things
if(condition_when_you_want_your_loop_to_stop){
flag = false;
}
}