HI感谢任何有关此问题的答案。即使在反复检查变量之后,我也无法让我的php表单工作。
这是表格标签的开头 -
<form name="sentMessage" action="contact.php" method="post" id="contactForm">
我的PhP如下 -
<?php
$myemail = 'nikhilnayak.in@gmail.com';
$name = check_input($_POST['name'], "Enter your name");
$email = check_input($_POST['email'], "Enter your E-mail ID");
$phone = check_input($_POST['phone'], "Enter your Contact #");
$refemail = check_input($_POST['refemail']);
if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/", $email))
{
show_error("E-mail address not valid");
}
$subject = 'New Website Lead' ;
$headers = "From: $name";
$message = "
Name: $name
E-mail: $email
Contact #: $phone
References:
$refemail
" ;
mail($myemail, $subject, $message, $headers);
header('Location: thankyou.html');
exit();
function check_input($data, $problem='')
{
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
if ($problem && strlen($data) == 0)
{
show_error($problem);
}
return $data;
}
function show_error($myError)
{
?>
[HTML BODY HERE}
<?php
exit();
}
?>
请大家,任何帮助都很有用。这已经上传,即使在现场直播也无法正常工作......
这是HTML表单 -
<form name="sentMessage" action="contact.php" method="post" id="contactForm">
<div class="row control-group">
<div>
<label style="margin-right:85px; font-size:16px;">Name</label>
<input type="text" class="form-control" placeholder="Name" id="name" required data-validation-required-message="Please enter your name.">
<p class="help-block text-danger"></p>
</div>
</div>
<div class="row control-group">
<div>
<label style="margin-right:20px; font-size:16px;">Email Address</label>
<input type="email" class="form-control" placeholder="Email Address" id="email" required data-validation-required-message="Please enter your email address.">
<p class="help-block text-danger"></p>
</div>
</div>
<div class="row control-group">
<div>
<label style="margin-right:15px; font-size:16px;">Phone Number</label>
<input type="tel" class="form-control" placeholder="Phone Number (+974)" id="phone" required data-validation-required-message="Please enter your phone number.">
<p class="help-block text-danger"></p>
</div>
</div>
<br>
<p>If you would like to refer someone else or if you have multiple e-mail IDs, enter them below</p>
<div class="row control-group">
<div>
<label style="margin-right:40px; font-size:16px;">References</label>
<input type="tel" class="form-control" placeholder="Email 1; Email 2; Email 3" id="refemail" required data-validation-required-message="Please the E-mail IDs.">
<p class="help-block text-danger"></p>
</div>
</div>
<br>
<div id="success"></div>
<div class="row" style="display:inline-block; text-align:center;">
<div class="form-group col-xs-12">
<button type="submit" class="btn btn-success btn-lg">Send</button>
</div>
</div>
</form>
更新----
HI GUYS,感谢您的回答...删除了PHP中的重新验证,它似乎重新指向感谢页面... 但我收到的电子邮件是空白的(没有$ name,$ phone等...)
新的PHP代码 -
$name = check_input($_REQUEST['name']);
$email = check_input($_REQUEST['email']);
$phone = check_input($_REQUEST['phone']);
$refemail = check_input($_REQUEST['refemail']);
我删除了以下代码。
if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/", $email))
{
show_error("E-mail address not valid");
}
更新
linil回答
答案 0 :(得分:1)
您的代码似乎没问题。
您应首先尝试在条件中包装mail()
和以下exit()
语句。就像现在一样,您在加载HTML之前尝试邮寄和退出,以便客户填写联系信息。
见下文:
您的新HTML
<form name="sentMessage" action="contact.php" method="post" id="contactForm">
<div class="row control-group">
<div>
<label style="margin-right:85px; font-size:16px;">Name</label>
<input type="text" class="form-control" placeholder="Name" id="name" name="name" required data-validation-required-message="Please enter your name.">
<p class="help-block text-danger"></p>
</div>
</div>
<div class="row control-group">
<div>
<label style="margin-right:20px; font-size:16px;">Email Address</label>
<input type="email" class="form-control" placeholder="Email Address" id="email" name="email" required data-validation-required-message="Please enter your email address.">
<p class="help-block text-danger"></p>
</div>
</div>
<div class="row control-group">
<div>
<label style="margin-right:15px; font-size:16px;">Phone Number</label>
<input type="tel" class="form-control" placeholder="Phone Number (+974)" id="phone" name="phone" required data-validation-required-message="Please enter your phone number.">
<p class="help-block text-danger"></p>
</div>
</div>
<br>
<p>If you would like to refer someone else or if you have multiple e-mail IDs, enter them below</p>
<div class="row control-group">
<div>
<label style="margin-right:40px; font-size:16px;">References</label>
<input type="tel" class="form-control" placeholder="Email 1; Email 2; Email 3" id="refemail" name="refemail" required data-validation-required-message="Please the E-mail IDs.">
<p class="help-block text-danger"></p>
</div>
</div>
<br>
<div id="success"></div>
<div class="row" style="display:inline-block; text-align:center;">
<div class="form-group col-xs-12">
<button type="submit" name="submit" class="btn btn-success btn-lg">Send</button>
</div>
</div>
</form>
您的新PHP
<?php
$myemail = 'nikhilnayak.in@gmail.com';
$name = check_input($_POST['name'], "Enter your name");
$email = check_input($_POST['email'], "Enter your E-mail ID");
$phone = check_input($_POST['phone'], "Enter your Contact #");
$refemail = check_input($_POST['refemail']);
if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/", $email))
{
show_error("E-mail address not valid");
}
$subject = 'New Website Lead';
$headers = "From: $name";
$message = "
Name: $name
E-mail: $email
Contact #: $phone
References:
$refemail
";
if ($name && $email)
{ //add a condition that validates the email for sending
mail($myemail, $subject, $message, $headers);
header('Location: thankyou.html');
exit();
}
function check_input($data, $problem = '')
{
echo $data;
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
if ($problem && strlen($data) == 0)
{
show_error($problem);
}
return $data;
}
function show_error($myError)
{
?>
[HTML BODY HERE}
<?php
exit();
}
?>
希望有所帮助。
更新:
尝试用此替换$header
:
$headers = "From: $name <nobody@".$_SERVER['SERVER_NAME'].">";
此外,请更换以下内容,以便我们了解您收到空白邮件的原因:
if ($name && $email)
{ //add a condition that validates the email for sending
print_r($message); exit;
/*
if Name, Email, Contact and References are not set.
It mean their name value are not still set in your HTML code
Note: while print_r is in effect. this page won't redirect.
we are debugging.
Remove the print_r line after you start getting expected values
and redirect will work fine.
*/
mail($myemail, $subject, $message, $headers);
header('Location: thankyou.html');
exit();
}
答案 1 :(得分:0)
试试这个
<?php
$myemail = 'nikhilnayak.in@gmail.com';
if(isset($_POST['name'] && $_POST['email'] && $_POST['phone'] && $_POST['refemail']){
$name = check_input($_POST['name'], "Enter your name");
$email = check_input($_POST['email'], "Enter your E-mail ID");
$phone = check_input($_POST['phone'], "Enter your Contact #");
$refemail = check_input($_POST['refemail']);
if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/", $email))
{
show_error("E-mail address not valid");
}
$subject = 'New Website Lead' ;
$headers = "From: $name";
$message = "
Name: $name
E-mail: $email
Contact #: $phone
References:
$refemail
" ;
mail($myemail, $subject, $message, $headers);
header('Location: thankyou.html');
exit();
}
function check_input($data, $problem='')
{
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
if ($problem && strlen($data) == 0)
{
show_error($problem);
}
return $data;
}
function show_error($myError)
{
//try to echo the html here instead
}