Question

我正在将url传递给服务器，并提供类似这样的数据，

     HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("firstname",firstname));
            nameValuePairs.add(new BasicNameValuePair("lastname", lastname));

           httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            HttpResponse response = httpclient.execute(httppost);

它给出了像这样的回复

{
      "message": "Successful",
    "data": {
        "user_id": 32,
        "firstname": "myname",
        "lastname": "lastname"
    }
 }

如何从上面的响应中获取user_id，或者还有其他任何方式。请告诉我如何解决这个问题。谢谢你提前

Answer 1

像这样：

try {
    JSONObject obj = new JSONObject(response.getBody());
    JSONObject objData = obj.getJSONObject("data");
    Integer userId = objData.getInt("user_id");
} catch (JSONException jsEx) {
    jsEx.printStackTrace();
}

Answer 2

这样做，

首先使用此方法获取响应数据，

public String getResponseBody(final InputStream instream) throws IOException, ParseException {
        if (instream == null) {
            return "";
        }
        StringBuilder buffer = new StringBuilder();
        BufferedReader reader = new BufferedReader(new InputStreamReader(instream, "utf-8"));

        String line = null;
        try {
            while ((line = reader.readLine()) != null) {
                buffer.append(line);
            }
        } finally {
            instream.close();
            reader.close();
        }
        return buffer.toString();
    }

然后，

JSONObject results = new JSONObject(getResponseBody(httpEntity.getContent()));
JSONObject user = results.getJSONObject("data");
String userid = user.getString("user_id")

Answer 3

在您的代码

之后添加此内容

HttpEntity httpEntity = response.getEntity();
String responseJson = EntityUtils.toString(httpEntity);

在这里，你将把你的json作为字符串作为回应。你必须解析这个json以得到这样的期望值。

try {
    JSONObject obj = new JSONObject(responseJson);
    JSONObject objData = obj.getJSONObject("data");
    Integer userId = objData.getInt("user_id");
} catch (JSONException jsEx) {
    jsEx.printStackTrace();
}

跳这会让你明白：）

如何存储服务器响应以及如何在我的应用程序中获取特定数据

3 个答案: