Question

的Kh-H0f2ZNYcxWYQtJvA-4jQ2rnm8WQSsVsNFkVRMYxpg-1417365081517,38606，＆＃34;最佳购买Co，Inc。＆＃34;，BBY01-694284011841

预期ans是

Kh-H0f2ZNYcxWYQtJvA-4jQ2rnm8WQSsVsNFkVRMYxpg-1417365081517＆＃34; Best Buy Co，Inc。＆＃34; BBY01-694284011841

但我正在

的Kh-H0f2ZNYcxWYQtJvA-4jQ2rnm8WQSsVsNFkVRMYxpg-1417365081517 ＆＃34;百思买公司公司＆＃34。 BBY01-694284011841

我使用了分裂

String s =＆＃34; ...＆＃34;;
String s [] = s.split（＆＃34;，＆＃34;）;

Answer 1

您可以对空白使用否定前瞻，以避免分割Best By Co和Inc.：

System.out.println(
    Arrays.toString(
        "Kh-H0f2ZNYcxWYQtJvA-4jQ2rnm8WQSsVsNFkVRMYxpg-1417365081517,38606,\"Best Buy Co, Inc.\",BBY01-694284011841"
        .split(",(?!\\s)")
    )
);

<强>输出

[Kh-H0f2ZNYcxWYQtJvA-4jQ2rnm8WQSsVsNFkVRMYxpg-1417365081517, 38606, "Best Buy Co, Inc.", BBY01-694284011841]

使用正则表达式在java中用逗号分隔字符串

1 个答案: