Question

我的mysql中有这个表：

| id | category_id | region_id | score | +----+-------------+-----------+-------+ | 1 | 1 | 1 | 78 | | 2 | 1 | 2 | 65 | | 3 | 1 | 3 | 98 | | 4 | 1 | 4 | 45 | | 5 | 1 | 5 | 78 | | 6 | 1 | 1 | 98 | | 7 | 1 | 2 | 32 | | 8 | 1 | 3 | 56 | | 9 | 1 | 4 | 89 | | 10 | 1 | 5 | 65 | +----+-------------+-----------+-------+

我想获得5个最新的id，但是根据区域ID命令我的结果表，所以我使用了这个代码

SELECT * 
  FROM tb_scores 
 WHERE category_id = 1 
 ORDER 
    BY id DESC
     , region_id ASC
 LIMIT 5

但是结果只将id作为desc而不是region_id作为ASC进行排序。简要解释一下我想要这种结果。

| id | category_id | region_id | score |
+----+-------------+-----------+-------+
|  6 |           1 |         1 |    98 |
|  7 |           1 |         2 |    32 |
|  8 |           1 |         3 |    56 |
|  9 |           1 |         4 |    89 |
| 10 |           1 |         5 |    65 |
+----+-------------+-----------+-------+

Answer 1

试试这个：

SELECT *
FROM   (SELECT *
        FROM   tb_scores
        WHERE  category_id = 1
        ORDER  BY id DESC,region_id ASC LIMIT 5) t
ORDER  BY region_id

在子查询中获取数据并在子查询结果上应用order by region_id。

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1 个答案: