Question

我有简单的表格，我存储了userID，UserName，Email，RegistrationDate ......

RegistrationDate是DateTime数据类型

当我要获取每个日期的用户数时，每行会得到1个，因为每行都有一个唯一的日期时间戳。

SELECT DATEPART(dd, RegistrationDate) AS DD, COUNT(userID)   
FROM USER_Table 
GROUP BY RegistrationDate 
order by RegistrationDate DESC

如果我有100个用户注册，ABove查询会给我100行。

我希望根据日期计算。我尝试了不同的东西但似乎什么都没有用。

Answer 1

试试这个：

SELECT Cast(RegistrationDate AS DATE),
       Count(userID)
FROM   User_Table
GROUP  BY Cast(RegistrationDate AS DATE)
ORDER  BY Cast(RegistrationDate AS DATE)DESC

Answer 2

您需要按CAST(RegistrationDate as Date)

进行分组

SELECT CAST(RegistrationDate as Date) AS [Date], COUNT(userID)   
FROM USER_Table 
GROUP BY CAST(RegistrationDate as Date)
order by CAST(RegistrationDate as Date) DESC

Answer 3

SELECT cast(RegistrationDate as Date) AS DD, COUNT(userID)   
FROM USER_Table 
GROUP BY cast(RegistrationDate as Date)
order by cast(RegistrationDate as Date) DESC

根据日期获取用户数

3 个答案: