Question

我有一个像下面提到的xml：

<Attributes>
  <Attribute>
    <EntryID>0</EntryID>
    <ContractID>227860</ContractID>
    <FieldID>10882</FieldID>
    <GroupID>0</GroupID>
    <InstanceID>0</InstanceID>
    <Value>C:\Users\laitkor\Downloads\BulkTest826.mp4</Value>
    <CreatedBy>615</CreatedBy>
    <CreatedOn>12/1/2014 6:51:04 AM</CreatedOn>
    <UpdatedBy>615</UpdatedBy>
    <UpdatedOn>12/1/2014 6:51:04 AM</UpdatedOn>
  </Attribute>
</Attributes>

我必须更改节点值＆＃39; Value＆＃39;从C:\Users\laitkor\Downloads\BulkTest826.mp4到BulkTest826.mp4。

我尝试使用以下方法更改值：

  XmlDocument xml = new XmlDocument();
        xml.LoadXml(nodes); 
        bool isMultimedia = false;
        XmlNodeList xnList = xml.SelectNodes("/Attributes/Attribute");
        foreach (XmlNode xn in xnList)
            {
            int FieldId = Convert.ToInt32(xn["FieldID"].InnerText);
            isMultimedia = true;
            if (isMultimedia) {
            string MultiMediaFilePath = xn["Value"].InnerText;
            createMultimediaFile(FieldId, MultiMediaFilePath, contractID);//todo
            string fileName = MultiMediaFilePath.Substring(MultiMediaFilePath.LastIndexOf('\\', MultiMediaFilePath.Length - 1));
            fileName = fileName.TrimStart('\\');
            xn.SelectSingleNode("/Attributes/Attribute/Value").InnerText = fileName;

                }
            retval = SiteProvider.ContractBulk.AddBulkContractField(nodes, contractID, groupID, sequenId, 1);//issue here
            return retval;
            }

但是我以XML格式获得的节点的价值没有更新的值＆＃39; Value＆＃39;在评论中提到的节点＆＃39;在这里发布＆＃39;

Answer 1

        XmlDocument xml = new XmlDocument();
        xml.LoadXml(nodes);
        bool isMultimedia = false;
        XmlNodeList xnList = xml.SelectNodes("/Attributes/Attribute");

        foreach(XmlNode node in xnList)
        {
            XmlNode n1 = node.SelectSingleNode("Value");

            //I will suppose that you need to do that for more than one Value node
            if(n1.InnerText.Contains(@"C:\Users\laitkor\Downloads\"))
            {
                n1.InnerText = n1.InnerText.Replace(@"C:\Users\laitkor\Downloads\", "");
            }
        }

我想你不止一次想要不同的文件。我曾经替换C:\Users\laitkor\Downloads\，如果位置可能不同，您可以找到最后\和substring的索引，直到此索引。

Answer 2

试试这个

using System;
using System.Linq;
using System.Xml.Linq;
using System.Xml.XPath;                 
using System.IO;

public class Program
{
    public static void Main()
    {
        //XElement xml = XElement.Load(xmlFile); //Load from file
        XElement xml=XElement.Parse(@"<Attributes>  <Attribute>    <EntryID>0</EntryID>    <ContractID>227860</ContractID>    <FieldID>10882</FieldID>    <GroupID>0</GroupID>    <InstanceID>0</InstanceID>    <Value>C:\Users\laitkor\Downloads\BulkTest826.mp4</Value>    <CreatedBy>615</CreatedBy>    <CreatedOn>12/1/2014 6:51:04 AM</CreatedOn>    <UpdatedBy>615</UpdatedBy>    <UpdatedOn>12/1/2014 6:51:04 AM</UpdatedOn>  </Attribute></Attributes>");
        var valueElements = xml.XPathSelectElements("//Attribute/Value");

        foreach(XElement valueElement in valueElements)
        {           
            valueElement.Value=Path.GetFileName(valueElement.Value);
            Console.WriteLine(valueElement.Value);
        }
    }
}

Answer 3

使用System.Linq.Xml命名空间中的XElement。更直观的XML解析。

var xml=
XElement.Parse(yourXml); // or load XElement.Load(file);
var node = xml.Descendants()
    .FirstOrDefault(x => x.Name == "Value" && x.Parent.Name =="Attribute"); 

node.Value="BulkTest826.mp4"; // If you only need one
// Or
var valueNodes = xml.Descendants("Value");
foreach(var val in valueNodes)
{
  // val.Value = "You new value";
}

Answer 4

你可以这样做：

        XmlNodeList nodes = doc.SelectNodes("Attributes/Attribute");

        foreach (XmlNode node in nodes)
        {
            node.SelectSingleNode("Value").InnerText = fileName;
        }

问题是你试图从节点/属性/属性节点/属性/属性/值

获取

更改xml节点值

4 个答案: