由7zip在python中打开存档（7z）文件时出错

Question

我一直在学习python得到了基础知识

为了更好，我一直在尝试创建一个程序来打开存档文件，而不是创建只是打开。

我可以轻松创建和打开7z文件但是当使用7zip创建存档时它不会打开它，任何人都知道为什么以及如何打开7zip创建的文件

  data = b"Insert Data Here"
  with lzma.open("file.7z", "w") as f:
    f.write(data)


  with lzma.LZMAFile("file.7z") as f:
        fc =f.read()
        print(fc)

追溯

Traceback (most recent call last):
  File "<string>", line 420, in run_nodebug
  File "C:\Users\<name>\Documents\Py\decompression.py", line 20, in <module>
    main()
  File "C:\Users\<name>\Documents\Py\decompression.py", line 15, in main
    fc =f.read()
  File "C:\Python33\lib\lzma.py", line 291, in read
    return self._read_all()
  File "C:\Python33\lib\lzma.py", line 244, in _read_all
    while self._fill_buffer():
  File "C:\Python33\lib\lzma.py", line 238, in _fill_buffer
    self._buffer = self._decompressor.decompress(rawblock)
_lzma.LZMAError: Input format not supported by decoder