任务是编写一个可以用RSA加密和解密消息的程序。
我开始写它，但是刚开始程序在我想决定是加密（e）还是解密（d）时不接受我的e。错误在哪里？
我该如何继续？我想我没有得到rsa系统..
谢谢！
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
/* Simple RSA:
encrypt text using a secure cryptographic function that makes decryption
impossible unless the recipient has the corresponding key for decryption.
*/
unsigned long long int p;
unsigned long long int q;
unsigned long long int N; // modulus for encryption and decryption
unsigned int e;
unsigned long long int d;
unsigned long long int phi;
unsigned int c;
unsigned int m;
signed int s;
signed int t;
unsigned long long int e_or_d;
int i = 0;
int main () {
/* Ask the user about the numbers N and e */
printf("Enter N: ");
scanf("%u", &N);
getchar();
printf("Enter e: ");
scanf("%u", &e);
getchar();
/* Ask the user if he wants to decrypt or encrypt a message */
while(1) {
printf("Encrypt or Decrypt [e/d]? ");
scanf("%2c", &e_or_d);
getchar();
if(e_or_d != e | d) {
return 0;
}
if(e_or_d = e) {
printf("Enter message: \n");
scanf("%u", &m);
getchar();
for (i = 0; i < m; i++) {
N = p*q;
phi = (p-1)*(q-1);
}
if(N < 0) {
return 0;
}
else if(N = 0) {
return 1;
}
else if(N = 1) {
return ?
}
return 0;
}
if(e_or_d = d) {
printf("Enter d: \n");
scanf("%u", &d);
getchar();
return 0;
}
return 0;
}
return 0;
}
答案 0 :(得分：0)
我不确定你想要实现的目标，我可能会误解这一点。但是在这里：
if(e_or_d != e | d) {
return 0;
}
这个：|是按位OR。我相信你的意思是：
if ((e_or_d != 'e') && (e_or_d) != 'd'))
return 0;
检查输入是char 'e'还是char 'd'。