Question

<?php


session_start();


$hostname="localhost"; //local server name default localhost


$username="root";  //mysql username default is root.


$password="";       //blank if no password is set for mysql.

$数据库=“总线票证预约”; //您创建的数据库名称

$con=mysqli_connect($hostname,$username,$password,$database);


 if(isset($_SESSION['id']))



{


include("config.php");



$uid = $_SESSION['id'];



$bus = $_GET['bus'];


$seat = $_GET['seat'];


$choice = $_GET['choice'];


$bust = $bus.'bus';


$date = date("Y-m-d"); 


 $query = mysqli_query($con,"Select * from bus where id ='$bus'");

 if($query){


    $re1 = mysqli_fetch_array($query);


        $bus_name = $re1['bus_name'];


        $from = $re1['from_stop'];


        $to = $re1['to_stop'];


        $dept_time = $re1['dept_time'];


        $arrival_time = $re1['arrival_time'];


        $distance = $re1['distance'];


        $fare = $re1['fare'];

}


    if($choice !='')


{


        if($choice=='W' && $seat==1)
{

$ query2 =“选择*来自$ bust，其中status ='可用'AND state ='$ choice'limit 0，$ seat”;

    $p = mysqli_query($con,$query2);


    $re = mysqli_num_rows($p);

        }


    else
        {

   $query2 = "Select * from $bust where status='Available' limit 0,$seat";

   $p = mysqli_query($con,$query2);

   $re = mysqli_num_rows($p);

}

   if($re>=$seat)
{

     while($r = mysqli_fetch_array($p))

{

     $id = $r['id'];

      $q3 = mysqli_query($con,"update $bust set status ='Booked' where id='$id'");

         $q4 = mysqli_query($con,"insert into user_history(user_id, bus_id,bus_name, from_stop ,

to_stop，booking_date，seat_no_booked，dept_time，distance，fare）

 values('".$uid."','".$bus."','".$bus_name."', '".$from."', '".$to."', '".$date."', '".$id."',

'“。$ dept_time。”'，'“。$ distance。”'，'“。$ fare。”'）“）;

    }


?>
         <script>

Answer 1

首先，学习如何发布问题。其次你用“Python”标记了这个问题，这是php代码。

并非他们中最好的一个。

在我的脚本mysqli_query（）中显示此错误：无法获取mysqli

1 个答案: