Question

我有一个查询，它返回退休次数最多的跑步者：

SELECT runnerName, COUNT(runner) Retired
FROM `lapInfo` A JOIN `runner` B
ON A.lapInfoRunnerNo = B.runnerNo
WHERE `lapInfoRetired`=1
GROUP BY runnerName
ORDER BY COUNT(lapInfoRunnerNo) DESC
LIMIT 1;

目前，如果两名选手都退役一次并且没有其他选手退役，我希望查询返回这两名选手，因为他们都退役了最多次。我尝试过MAX（）而不是LIMIT，但它仍然只返回一个值。

我正在使用MySQL。

由于

Answer 1

您可以在子查询中获取最大退休计数，然后将其进行比较以获得具有最大退休计数的所有参与者

SQL Fiddle

SELECT runnerName, runnerno 
from runner r
join lapinfo l
on r.runnerno = l.lapinfoRunnerNo
group by runnerName
having sum(lapinfoRetired=1) =(
  SELECT SUM(lapInfoRetired=1) as TotalRetired 
  FROM lapInfo
  GROUP BY lapInfoRunnerNo
  ORDER BY SUM(lapInfoRetired=1) desc
  LIMIT 1 )

Answer 2

如果您不介意将这些名称作为逗号分隔列表，您可以这样做：

SELECT GROUP_CONCAT(runnerName), Retired
FROM (SELECT runnerName, COUNT(runner) as Retired
      FROM `lapInfo` A JOIN
           `runner` B
           ON A.lapInfoRunnerNo = B.runnerNo
      WHERE `lapInfoRetired`=1
      GROUP BY runnerName
     ) r
GROUP BY Retired
ORDER BY Retired DESC
LIMIT 1;

顺便说一句，使用表别名是个好主意。但是当它们是表名的缩写时更好。我建议li为lapinfo，r为runner。

SELECT最高值，如果共享最高值，则为值

2 个答案: