Question

嘿伙计们我对此非常陌生，所以如果我在这里缺少一些完全愚蠢的东西，我很抱歉。我有以下注册表格。在URL http://www.rockaholics-cologne.de/root/signup.php?e=cataras@gmx.de中，我正在尝试提交值e。但是，在所有情况下，e都是空的或未定义的：

 <?php
   // Ajax calls this REGISTRATION code to execute
   if(isset($_POST["u"])){
   // CONNECT TO THE DATABASE
   include_once("php_includes/db_conx.php");
   // GATHER THE POSTED DATA INTO LOCAL VARIABLES
    $u = preg_replace('#[^a-z0-9]#i', '', $_POST['u']);
    $p = $_POST['p'];
    $e = $_GET['e'];
    echo "test";
    echo "$e";
    // GET USER IP ADDRESS
    $ip = preg_replace('#[^0-9.]#', '', getenv('REMOTE_ADDR'));
    // DUPLICATE DATA CHECKS FOR USERNAME AND EMAIL
    $sql = "SELECT id FROM team WHERE username='$u' LIMIT 1";
    $query = mysqli_query($db_conx, $sql); 
    $u_check = mysqli_num_rows($query);
    // FORM DATA ERROR HANDLING
    if($u == "" || $p == ""){
        echo "The form submission is missing values.";
        exit();
    } else if ($u_check > 0){ 
        echo "The username you entered is alreay taken";
        exit();
    } else if (strlen($u) < 3 || strlen($u) > 16) {
        echo "Username must be between 3 and 16 characters";
        exit(); 
    } else if (is_numeric($u[0])) {
        echo 'Username cannot begin with a number';
        exit();
    } else {
    // END FORM DATA ERROR HANDLING
        // Begin Insertion of data into the database
        // Hash the password and apply your own mysterious unique salt
        $cryptpass = crypt($p);
        include_once ("php_includes/randStrGen.php");
        $p_hash = randStrGen(20)."$cryptpass".randStrGen(20);
        // Add user info into the database table for the main site table
        $sql = "UPDATE team
                SET username='$u',password='$p_hash',ip='$ip',signup=now(),lastlogin=now(),notecheck=now()
                WHERE email='$e'";
        $query = mysqli_query($db_conx, $sql); 
        $uid = mysqli_insert_id($db_conx);
        // Create directory(folder) to hold each user's files(pics, MP3s, etc.)
        if (!file_exists("user/$u")) {
            mkdir("user/$u", 0755);
        }
        // Email the user their activation link
        $to = "$e";                          
        $from = "auto_responder@yoursitename.com";
        $subject = 'Account Activation';
        $message = '<!DOCTYPE html><html><head><meta charset="UTF-8">
        <title>yoursitename Message</title></head>
        <body style="margin:0px; font-family:Tahoma, Geneva, sans-serif;">
        <div style="padding:10px; background:#333; font-size:24px; color:#CCC;">
        <a href="http://www.yoursitename.com"><img src="http://www.rockaholics-cologne.de/root/images/logo.png" width="36" height="30" alt="yoursitename" style="border:none; float:left;"></a>Account Activation</div>
        <div style="padding:24px; font-size:17px;">Hello '.$u.',<br /><br />Click the link below to activate your account when ready:<br /><br /><a href="http://www.rockaholics-cologne.de/root/activation.php?id='.$uid.'&u='.$u.'&p='.$p_hash.'">Click here to activate your account now</a><br /><br />Login after successful activation using your:<br />* Username: <b>'.$u.'</b></div></body></html>';
        $headers = "From: $from\n";
        $headers .= "MIME-Version: 1.0\n";
        $headers .= "Content-type: text/html; charset=iso-8859-1\n";
        mail($to, $subject, $message, $headers);
        echo "signup_success";
        exit();
    }
    exit();
}
?>

填写表单时，我会在数据库中输入新条目。但它既没有给我发电子邮件，也没有在指定的电子邮件中更新数据库。它只是用空白电子邮件更新所有条目。脚本中的回显“$ e”也没有返回任何内容。

我用这段代码检查：

<?php

    echo "<pre>";
    print_r($_GET);
    echo "</pre>";
    $e = $_GET['e'];
    echo "$e";

?>

在这种情况下，它确实返回一个带有[e] =cataras@gmx.de的数组，它还打印出$ e。但为什么它不能在另一个skript工作？我使用完全相同的方法从URL获取e。

当我运行我的Javascript函数时：

function signup(){
    var u = _("username").value;
    var p1 = _("pass1").value;
    var p2 = _("pass2").value;
    var status = _("status");
    if(u == "" || p1 == "" || p2 == ""){
        status.innerHTML = "Fill out all of the form data";
    } else if(p1 != p2){
        status.innerHTML = "Your password fields do not match";
    } else {
        _("signupbtn").style.display = "none";
        status.innerHTML = 'please wait ...';
        var ajax = ajaxObj("POST", "signup.php");
        ajax.onreadystatechange = function() {
            if(ajaxReturn(ajax) == true) {
                if(ajax.responseText.replace(/^\s+|\s+$/g, "") == "signup_success"){
                    status.innerHTML = ajax.responseText;
                    _("signupbtn").style.display = "block";
                } else {
                    window.scrollTo(0,0);
                    _("signupform").innerHTML = "OK "+u+", check your email inbox and junk mail box at <u>"+e+"</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.";
                }
            }
        }
        ajax.send("u="+u+"&p="+p1);
    }
}

我得到Uncaught ReferenceError：e未定义。该网站停在“请等待......”。我刚拿出js中的+ e +来到上面的php。对不起，很长的帖子，但我真的没有想法。谢谢！

Answer 1

我认为$ _GET [＆＃39; e＆＃39;]无法在您的原始脚本中运行，因为它没有从您的表单页面传递到该处理脚本。我访问了您提供的网址（http://www.rockaholics-cologne.de/root/signup.php?e=cataras@gmx.de）。请注意，当您提交表单时，＆＃34; e＆＃34;在您的URL中没有传递给处理您的脚本的任何内容。在您的表单中，您需要执行以下操作：

<form action="{yourscripturl}?e=<?php echo $_GET['e']?>" {rest of form tag}>

或者，添加一个隐藏来保存＆＃34; e＆＃34;的值，然后在处理脚本上使用$ _POST [＆＃39; e＆＃39;]而不是$ _GET [＆＃39;] E＆＃39;]

<input type="hidden" name="e" value="<?php echo $_GET['e']?>" />

PHP和Javascript - 未定义变量的问题

1 个答案: